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KonstantinChe [14]
2 years ago
12

Which of these contributors will transfer the greatest amount of carbon into the atmosphere while reabsorbing the least amount o

f carbon from the atmosphere?
A. the ocean
B. changing land use
C. vegetation and soil
D. fossil fuels and industry
Biology
2 answers:
svlad2 [7]2 years ago
7 0
D fossil fuels and industry
ss7ja [257]2 years ago
3 0
Fossil fuels and industry
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Which best illustrates the result of the process of meiosis?
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“A daughter looks different from both her mother and her father” best illustrates the result of the process of meiosis.

 

Meiosis<span> is a type of cell division that reduces the number of chromosomes in the parent cell by half and produces four gamete cells. This process is required to produce egg and sperm cells for sexual reproduction.</span>

 

The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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the mutation of the brca1 gene normally functions to ensure? a)breast cancer cells duplicate b)suppress tumor function c)the per
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I believe the answer is B!
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3 years ago
Day 1: 4 km Day 2: 10 km Day 3: 12 km Day 4: 12 km Day 5: 18 km Day 6: 24 km
yKpoI14uk [10]

Answer:

In order to find average speed during each interval, we need to divide the distance during those intervals with the period of time. So, for the first interval (day 0 to day 2) hawksbill started from 0 and reached 10 kilometers by the end of the second day. That means that it crossed 10 kilometers in 2 days, so the average speed is 10/2 which is 5 km/day. Similarly, we can calculate speed for other intervals:

• day 2 - day 3: it went from 10 to 12 km in one day, which means it crossed 2 km in one day, so the average speed is 2/1 = 2 km/day

• day 3 - day 4: at the end of the third day it reached 12 km and at the end of the day 4 it remained at 12 km. That means the hawksbill wasn't moving in that interval so the speed was 0

• day 4 - day 5: it went from 12 km to 18 km, which means it crossed 18-12=6 km in one day, so the average speed is 6/1=6 km/day

• day 5 - day 6: it went from 18 to 24 km, which means it crossed 24-18=6 km in one day, so the speed was 6/1=6 km/day

So, to summarize, during the first interval turtle was moving with average speed of 5 km/day, then 2 km/day, in the third interval it wasn't moving and in the last two intervals, it moved in average speed of 6 km/day.

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Describe the epithelium found in the uterine tube.
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3 years ago
A model of sympatric speciation is shown here analyze the model and assess which types of isolation could result in the speciati
AfilCa [17]

Answer:

A, B and D

Explanation:

just did it on USAtestprep

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2 years ago
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