Cell wall.
Made of cellulose and acts as a stronger cell membrane in a plant cell
Answer:
The options
1
Have dilute urine."
2
Be unable to urinate."
3
Produce dark red urine."
4
Experience some burning on urination."
The CORRECT ANSWER IS 4
4
Experience some burning on urination."
Explanation:
Due to the trauma affecting the mucous membranes of the urinary tract, burning on urination is a more likely response, this sensation gets to reduce with time. This will stop the urine from further dilution once the frequent continuous bladder irrigation is stoped and removed. Although, the urine may show a slight pink tinge which results from the trauma after the surgery and the effect of the catheter that is noticed. A difficulty to urinate won't be felt except the indwelling catheter is removed earlier than it should expected and edema still occurs in the urethra. Production of dark red urine is an indicative factor for hemorrhage, which ought not to be seen.
The chance that a certain event will occur is known as its probability.
Hope this helps!
-Payshence xoxo
Answer:
1) CO₂
2) 0.2551 g
Explanation:
The balanced reactions are:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
1) The gas produced is CO₂.
2) Calculate mass of CaCO₃:
(0.5236 g) (0.4230) = 0.2215 g CaCO₃
Convert to moles:
(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃
Find moles of CaCO₃:
(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂
Convert to mass:
(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂
Calculate mass of MgCO₃:
(0.5236 g) (0.5770) = 0.3021 g MgCO₃
Convert to moles:
(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃
Find moles of MgCO₃:
(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂
Convert to mass:
(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂
Total mass of CO₂:
0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂
