P(x) = 1 - 2x² +3x +2x⁵
has one variable, x, and has terms of degree 0, 2, 1, and 5. The highest degree is 5, so it is a 5th-degree polynomial in x.
To solve for this, if our equation is:
-3(n-2) = 12
Then we must use the distributive property.
The distributive property allows us to multiply the outside number/variable by all inside numbers/variables.
It will look like this:
-3(n) + -3(-2)
-3n + 6 = 12 is our new equation.
To solve for n, we need to get -3n by itself and then simplify.
Subtract 6 from both sides.
-3n = 6
Divide both sides by -3 to get n.
n = -2
I hope this helps!
Answer: 6.7inch
Step-by-step explanation:
From the question, we are informed that Emma made a scale model of the Sam Houston's monument and that the monument's actual height is 67 ft tall but Emma is using a scale where 1 inch is 10 ft.
The height of Emma's model will therefore be 67ft divided by 10 since he's using a scale of 1:10. This will be:
= 67/10
= 6.7inch
Answer:
There are at least two runners whose times are less than 9 seconds apart.
Step-by-step explanation:
Let's assume that Tₙ is the time of the n-th runner, we know that:
6 min < Tₙ < 7 min
knowing that:
1 min = 60 s
We can rewrite this as:
6*60 s < Tₙ < 7*60 s
360 s < Tₙ < 420 s
We know that there are 7 runners, and we want to see if we can conclude that there are two runners whose times are less than nine seconds.
So, the smallest time allowed in seconds is 361 seconds (the first value larger than 360 seg) while the largest time allowed is 419 seconds (the largest time allowed smallest than 420 seconds).
Now, let's assume that the first runner has the smallest time:
then:
T₁ = 361 s
Now let's add 9 seconds to the time of each runner (here we want to check that we can have all the runners with exactly 9 seconds apart in their times, so we will prove that the statement is false), then:
T₂ = 361s + 9s = 370s
T₃ = 370s + 9s = 379s
T₄ = 379s + 9s = 388s
T₄ = 388s + 9s = 397s
T₅ = 397s + 9s = 406s
T₆ = 406s + 9s = 415s
T₇ = 415s + 9s = 424s
But 424s > 420s
So this is not allowed (as the maximum time allowed was 419 s), so at least two of the runners must have times that are less than 9 seconds apart.
Then; Can you conclude that there are two runners whose times are less than nine seconds apart? Yes.
Answer:
7/44
Step-by-step explanation:
you can't simply subtract 1/11 from 1/4 because the denominators are not the same . Meaning you have to convert the denominators into a similar number. Transformers in even number and a consecutive number while 11 is an odd number and a prime number they don't really agree on anything 11 can only be divided by itself and 1 wall for can be divided by a multitude of things. Because of them not exactly agreeing on any specific category , you have to multiply them by each other . So your new fractions should look like 11 / 44 and 4 / 44 . from there you can easily subtract 4 from 11 and get 7 / 44 now normally you can reduce these types of fractions but because seven can only be divided by itself and 44 is not a factor of 7 you cannot reduce this fraction .