Answer : (-∞,-1) U (-1, 1)
We need to find the interval(s) over which the function is increasing
We look at the intervals of x where the graph is increasing
Increasing interval of the graph is the part where the graph goes up.
At first the graph starts increasing and it increases till x=-1
So the first increasing interval is -infinity to -1 . We write it as (-∞,1)
Now, we look at the part where the graph changes direction
In the middle inverted U shaped graph , the graph starts increasing at x=-1 and increases till it changes direction. The graph is increasing till x=1
so second increasing interval is x=-1 to 1. we write it as (-1,1)
Now combine both intervals by a 'U' union
(-∞,-1) U (-1, 1)
Answer:
14.2 years
Step-by-step explanation:
The multiplier of the population each year is 1 +5% = 1.05, so after n years the population has been multiplied by 1.05^n. You want to find the value of n that makes this expression equal to 2:
2 = 1.05^n
log(2) = n·log(1.05) . . . . . take logarithms
log(2)/log(1.05) = n ≈ 14.2
Growing at a rate of 5% per year, it will take about 14.2 years for the population to double.
1000+200+00+6=1206 is how it looks in expanded form.
Answer:
220.00
-185.00
= 35.00 the difference of what was paid at the same prices.
<span>g(x) = 6(4)x, Section A is from x = 0 to x = 1. Your "6(4)x" needs to be written as
</span><span>g(x) = 6(4)^x, where the " ^ " indicates exponentiation.
The average rate of change of g(x) from x= 0 to x=1 is:
6(4)^1 - 6(4)^0 24 - 6
a.r.c. = ----------------------- = ----------- = 18 (answer)
1-0 1
Now do the same thing for x = 1 to x = 2.</span>