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scZoUnD [109]
3 years ago
14

2(3-q)+5=9 solve for q

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0

Answer:

q = 1

Step-by-step explanation:

2(3 - q) + 5 = 9

* Expand the brackets

6 - 2q + 5 = 9

Separate the terms/variables and the integers.

6 + 5 - 9 = 2q

2 = 2q

1 = q

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3 years ago
Prove that√P is irrational for any prime number P​
Luda [366]

Answer:

Step-by-step explanation:

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3 years ago
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2 years ago
What is the answer to -6n^2 - 5n - 7 = -8
soldi70 [24.7K]

Answer:

n = \frac{1}{3} , n = \frac{1}{2}

Step-by-step explanation:

6n² - 5n - 7 = - 8 ( add 8 to both sides )

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Consider the product of the factors of the coefficient of the n² term and the constant term which sum to give the coefficient of the n- term

product = 6 × 1 = 6 and sum = - 5

The factors are - 3 and - 2

Use these factors to split the n- term

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3n(2n - 1) - 1(2n - 1) = 0 ← factor out (2n - 1) from each term

(2n - 1)(3n - 1) = 0 ← in factored form

Equate each factor to zero and solve for n

3n - 1 = 0 ⇒ 3n = 1 ⇒ n = \frac{1}{3}

2n - 1 = 0 ⇒ 2n = 1 ⇒ n = \frac{1}{2}

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Read 2 more answers
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