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Goryan [66]
4 years ago
14

you roll a number cube twice. find P(even, then not 2). write the probability as a fraction in simplest form

Mathematics
1 answer:
Lemur [1.5K]4 years ago
7 0
P(even number):
3/6 or 1/2
P( not 2):
5/6

5/6×1/2=5/12 is your final answer. Hope it help!
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What is the value of h in the figure below ? in this diagram BAD and CBD
xz_007 [3.2K]
The answer  is the option E: E. 8
 The explanation is shown below:
 1. You have that the triangles shown in the figure attached, are similar, therefore, you can calculate h as following:
 (20-4)/h=h/4
 16/h=h/h
 2. Now, solve for h:
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6 0
3 years ago
Read 2 more answers
For what value(s) of r is 5r-6=7+5r?
salantis [7]
This equation is false so no solutions because if u cancel out 5r on both sides then simplify, -67 = 7 cant be right so its false.
8 0
3 years ago
Look at the question below
alexira [117]

Answer: D) The balloon

Explanation:

Ignore the "above sea level" and "below sea level" portions. Focus purely on the numbers themselves. The largest value is the furthest away from sea level. The smallest value is closest to sea level.

Therefore, the balloon is furthest from sea level because 27 is the largest of the four values (5, 12, 18, 27).

3 0
3 years ago
Find parametric equations for the line through the point (0, 3, 2) that is parallel to the plane x + y + z = 5 and perpendicular
kozerog [31]
Hello : 
let A(0,3,2) and (Δ) this line , v vector   parallel to (<span>Δ).
M</span>∈ (Δ) : vector (AM) = t v..... t ∈ R

1 )    (Δ)  parallel to the plane x + y + z = 5 : let  : n an vector <span>perpendicular 
to the plane : n </span>⊥ v   ....   n(1,1,1) so : n.v =0  means : n.vector (AM) = 0
(1)(x)+(1)(y-3)+(1)(z -2) =0      ( vector (AM) = ( x, y -3 , z-2 )
x+y+z - 5=0 ...(1)

2)  (Δ) perpendicular to the line (Δ') : x = 1+t  , y = 3 - t , z = 2t :
vector (u) ⊥ v     .... vector(u) parallel to (Δ')  and vector(u) = (1 , -1 ,1)
vector (u) ⊥ vector (AM) means : 
(1)(x)+(-1)(y-3)+(2)(z -2) =0
x - y+2z - 1 = 0 ...(2)
so the system : 
x+y+z - 5=0 ...(1)
x - y+2z - 1 = 0 ...(2)
 (1)+(2) :   2x+3z - 6 =0
x = 3 - (3/2)z
subsct in (1) :    3 - (3/2)z  +y +z - 5 =0
y = 1/2z +2
let : z=t     
an parametric equations for the line (Δ) is :  x = 3 - (3/2)t
                                                                      y = (1/2)t +2
                                                                      z=t

verifiy : 
1) (Δ)  parallel to the plane x + y + z = 5 : 
(-3/2 , 1/2 ,1) <span>perpendicular to (1,1,1)
</span>because : (1)(-3/2)+(1)(1/2)+(1)(1) = -1 +1 = 0
2) (Δ) perpendicular to the line (Δ') :
 (-3/2 , 1/2 ,1) perpendicular to (1,-1,2)
because : (1)(-3/2)+(-1)(1/2)+(1)(2) = -2 +2 = 0
A(0, 3, 2)∈(Δ) : 
0 = 3-(3/2)t
3 = (1/2)t+2
2 =t
same :  t = 2

3 0
3 years ago
Five students are competing in a race. In how many different
Dimas [21]

Answer:

120

Step-by-step explanation:

• we need to find the number of the possible orderings

of this five students.

•• which we can simulate to a permutation

of 5 objects.

••• and we know that The number of permutations

of 5 distinct objects is 5!.

5! = 5×4×3×2×1 = 120

there are six permutations of the set {1, 2, 3}, namely (1, 2, 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), and (3, 2, 1). These are all the possible orderings of this three-element set.

The number of permutations of n distinct objects is n factorial, usually written as n!, which means the product of all positive integers less than or equal to n.

6 0
2 years ago
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