The discount to be increased so that he can gain only 15% is 8%.
<h3>What is a discount? </h3>
- Discounts are given when a reduction in the price is permitted to promote more purchases or timely payments. Discounts are divided into Trade reduction: The discount granted when substantial purchases are made is referred to as a trade discount.
- Discounts are given when a reduction in the price is permitted to promote more purchases or timely payments. Discounts are divided into Trade reduction: The discount granted when substantial purchases are made is referred to as a trade discount.
- Since sales discounts lower the cost of a product, they are not considered costs. These monetary discounts provided to consumers do, however, have an impact on a company's financial statements. Thus they must be reported as a decrease in revenue under the accounts receivable line item.
How much is the discount to be increased so that he can gain only 15%:
The cost price of the goods - y.
The selling price of the goods - x.
The selling price is
1.2y (100% + 20% = 120%).
The refrigerator was sold at 13% VAT at Rs. 10848:
=> 1.2y + 13%(1.2y) = 10848
=> 1.2y + 0.156y = 10848
=> 1.356y = 10848
=> y = 8000
Thus, the cp is Rs 8000.
The selling price is:
=> 0.96x = 1.2y
=> 0.96x = 1.2(8000)
=> x = 10000
The selling price is Rs. 10000
For a profit of 15%, that is 1.15(8000) = 9200, the discount is:
(1 - discount)10000 = 9200
1 - discount = 0.92
Discount = 1 - 0.92 = 0.08 or 8%
How much is the discount to be increased so that he can gain only 15%: Discount=8%
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Answer:
(y + 2) (3y - 4)
Step-by-step explanation:
1. 3y^2 + 2y - 8
Rewrite the expression.
2. 3y^2 + 6y - 4y - 8
Factor the expression.
3. 3y(y + 2) - 4(y + 2)
Factor the expression once again.
4. (y + 2) (3y - 4)
Answer:m=250
Step-by-step explanation:
0.1m+8-3=30
0.1m+5=30
0.1m=25
0.1 times 250=25
m=250
Answer:
3m/seconds
Step-by-step explanation:
In this problem we are required to solve for linear speed of the rotating wheel
The linear speed =angular speed x raduis
Given data
Radius r= 50cm
Converting from cm to m
50/100= 0.5m
Angular velocity w= 6rad/s
V=wr
V= 6*0.5m
V=3m/s
The linear speed is 3m/seconds