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2 years ago

15

Barb is making a bead necklace she strings won't Whitebead then three blue beads that one white bead and Soren write the numbers

for the first eight beads that are white what is a rule for the pattern

1 answer:

storchak [24]2 years ago

4 0

Can you repeat the question please?

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Suppose y varies directly with x. if y=7 when x=2, find y when x=3

DENIUS [597]

7/2=y/3

21=2y

Y=21/2

Hope this helps!

6 0

2 years ago

I need help with the coordinate plane

alexira [117]

Answer:

The -7 changes to 7 and the ordered pair of the new point is (4,7)

The -2 changes to 2 and the ordered pair of the new point is (2,-5)

Step-by-step explanation:

Hope this helped.

7 0

3 years ago

A bricklayer is able to set 2.5 bricks in one minute. How many bricks can he set in 8 hours?

pochemuha

Given:

A bricklayer is able to set 2.5 bricks in one minute.

Required:

To find the number of bricks can he set in 8 hours.

Explanation:

8 hours =480 minutes.

2.5 bricks in one minute.

So for 480 minutes,

$\begin{gathered} =2.5\times480 \\ \\ =1200 \end{gathered}$

Final Answer:

1,200 bricks can he set in 8 hours.

5 0

1 year ago

Simply the following expression. (v-2+3v3^) + (4v3^+7v+3)

Nina [5.8K]

Answer:

<em>Hope</em><em> </em><em>this is</em><em> </em><em>correct</em><em> </em>

Step-by-step explanation:

HAVE A GOOD DAY!

4 0

2 years ago

How can i differentiate this equation?

Dmitry_Shevchenko [17]

$\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}$

$\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}$

$\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}$

8 0

3 years ago