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ZanzabumX [31]
3 years ago
12

Leanne runs on the treadmill and rides the exercise bike at the gym to stay in shape. She burns 15 calories per minute on the tr

eadmill and 9 calories per minute on the bike. She wants to ride the bike 2.5 times as long as she runs on the treadmill and burn a total of 580 calories. The system of equations below can be used to find the number of minutes, t, she should run on the treadmill and the number of minutes, b, she should ride the bike. According to this system of equations, can Leanne meet both her goals? A. No, she cannot ride the exercise bike a negative number of minutes. B. Yes, she can ride the exercise bike for 15 minutes 28 seconds. C. Yes, she can run on the treadmill for 15 minutes 28 seconds. D. No, she cannot run on the treadmill for a fractional number of minutes.
Mathematics
1 answer:
sergiy2304 [10]3 years ago
8 0

Answer: C.

Explanation: i just took it. and got a 100. :)

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You’re answer is y=-1/1.5x+2.5
Explanation
2.5 is you’re y intersect and you go over one < and up 1.5
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Does (-2)^n/( 3^n+1) converge or diverge?
hodyreva [135]
\left|\dfrac{(-2)^n}{3^n+1}\right|=\dfrac{2^n}{3^n+1}

As n\to\infty, the sequence a_n=\left(\dfrac23\right)^n converges to zero.

If you're talking about the infinite series

\displaystyle\sum_{n\ge0}\dfrac{(-2)^n}{3^n+1}

well we've shown by comparison that this series must also converge because we know any geometric series \sum\limits_n r^n will converge as long as |r|.
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4 years ago
find the x-intercepts and the coordinates of the vertex for the parabola Y equals negative X squared plus 8X -12. If there’s mor
Oksanka [162]

Answer:

x = 2, and 6

x = 2 , 6

Step-by-step explanation:

The quadratic function to analyze is: y = -x^2+8x-12

In order to find where the corresponding parabola intercepts the x axis, we set it equal to zero (y = 0):

y = -x^2+8x-12\\0 = -x^2+8x-12\\x^2-8x+12=0

This equation is easy to solve by factoring. We look for a air of integer numbers whose product equals the constant term "12", and whose combinig renders the coefficient of the middle term of the trinomial "-8".

The two such numbers are "-2" and "-6". We use them to split the middle term, and then solve by factoring by grouping:

x^2-8x+12=0\\x^2-2x-6x+12=0\\(x^2-2x)+(-6x+12)=0\\x(x-2)-6(x-2)=0\\(x-2)(x-6)=0

For the product of two factors to render zero, we need either one to be a zero.This means that (x-2)=0 (that is x = 2), or (x-6)=0 (that is x = 6).

So, there are two x-intercepts: x= 2, and 6

3 0
3 years ago
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