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I am Lyosha [343]

3 years ago

13

Mr. Peterson sold a parcel of land and decided to share half of the amount he got among his three children Jane, Peter and marth

a in the ratio 4:5:7 respectively and according to their ages. the youngest child, who is 12 years old, received a$2000. how much money did peter and martha received?

2 answers:

Ugo [173]3 years ago

8 0

Answer:

$6,000

Step-by-step explanation:

If $y$ is the amount of money a child receives, and $x$ is the total amount being divided among the children, then

Jane's share: $y = \frac{4}{4+5+7} * x = \frac{4}{16}x$

Peter's share: $y = \frac{5}{4+5+7} * x = \frac{5}{16}x$

Martha's share: $y = \frac{7}{4+5+7} * x = \frac{7}{16}x$

We know Jane got $2000, so we can use that to solve for $x$ :

$\frac{4}{16} x = 2000$

$x = \frac{16}{4} * 2000 = 8000$

Plug this x value in to find how much Peter and Martha received:

$\frac{5}{16} * 8000 + \frac{7}{16} * 8000 = $6000$

aliya0001 [1]3 years ago

5 0

Answer:

60,000

Step-by-step explanation:

Jane-2000

Peter-ratio of 5=25000

Marta-ratio of 7=35000

25000+35000

60000

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This angles are in the first quadrant so we pick the positive values.

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$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

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The correct answer is D

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