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I am Lyosha [343]
3 years ago
13

Mr. Peterson sold a parcel of land and decided to share half of the amount he got among his three children Jane, Peter and marth

a in the ratio 4:5:7 respectively and according to their ages. the youngest child, who is 12 years old, received a$2000. how much money did peter and martha received?
Mathematics
2 answers:
Ugo [173]3 years ago
8 0

Answer:

$6,000

Step-by-step explanation:

If y is the amount of money a child receives, and x is the total amount being divided among the children, then

Jane's share:  y = \frac{4}{4+5+7} * x = \frac{4}{16}x

Peter's share:  y = \frac{5}{4+5+7} * x = \frac{5}{16}x

Martha's share:  y = \frac{7}{4+5+7} * x = \frac{7}{16}x

We know Jane got $2000, so we can use that to solve for x:

\frac{4}{16} x = 2000

x = \frac{16}{4} * 2000 = 8000

Plug this x value in to find how much Peter and Martha received:

\frac{5}{16} * 8000 + \frac{7}{16} * 8000 = $6000

aliya0001 [1]3 years ago
5 0

Answer:

60,000

Step-by-step explanation:

Jane-2000

Peter-ratio of 5=25000

Marta-ratio of 7=35000

25000+35000

60000

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Answer:

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Step-by-step explanation:

Formula for area of a trapezoid:

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Using the following information we plug in the values into the formula

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Step-by-step explanation:

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