Find the 6th term of the geometric sequence, given the first term and common ratio a1= 5 and r=3/2
1 answer:
<u>Answer</u>
37.96875
<u>Explanation</u>
In geometric sequence we use the formula below to find the nth of a sequence.
Tn = ar⁽ⁿ⁻¹⁾
Where a ⇒ first term
n ⇒ the term we are looking for
T₆ = 5 × (3/2)⁶⁻¹
= 5 × (3/2)⁵
= 5 × 243/32
= 1215/32
= 37 31/32
= 37.96875
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