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2 years ago

The question is in the picture

Mathematics

1 answer:

Dominik [7]2 years ago

3 0

Answer:

this look hard what grade

Step-by-step explanation:

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5. When choosing a movie to watch on Netflix, 45% of them are comedies, 30%

baherus [9]

The probability of choosing a horror movie or a comedy is 75%.

<h3>What are probabilities?</h3>

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

<h3>What is the probability of choosing a horror movie or a comedy?</h3>

45% + 30% = 75%

To learn more about probability, please check: brainly.com/question/26321175

4 0

2 years ago

Which set of data contains two outliers?

wariber [46]

Answer:

D: 101, 135, 131, 99, 138, 136, 140

Step-by-step explanation:

edg2020 (do not get this confused with the question: "which set contains no outliers"

4 0

2 years ago

Read 2 more answers

Probabilities are _____ one.

katovenus [111]

D.greater than or equal to one

6 0

3 years ago

Read 2 more answers

the container overflowed because the kids tried to pour in 3 and 3/5 times the amount it would hold. if they tried to pour in 28

ANEK [815]

Answer: 80 Gallons

Explanation:

$3 \frac{3}{5} = 3\frac{6}{10} = 3.6 \\ \frac{288}{3.6} = 80$

8 0

3 years ago

Int(1 \(1 + {e}^{x} )

Andreyy89

Answer:

$\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx}= x - \ln(1 + e^{x}) + C\end{aligned}$ .

Step-by-step explanation:

The first derivative of the denominator $1 + e^{x}$ is $e^{x}$ . Rewrite the fraction to obtain that expression on the numerator.

$\begin{aligned}\frac{1}{1 + e^{x}} &= \frac{1 + e^{x}}{1 + e^{x}} - \frac{e^{x}}{1+e^{x}}\\&=1-\frac{e^{x}}{1+e^{x}}\end{aligned}$ .

In other words,

$\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx} &= \int{dx} - \int{\frac{e^{x}}{1+e^{x}}\cdot dx}\end{aligned}$ .

Apply $u$ -substitution on the integral $\displaystyle \int{\frac{e^{x}}{1+e^{x}}\cdot dx}$ :

Let $u = 1 + e^{x}$ . $u > 1$ .

$du = e^{x}\cdot dx$ .

$\displaystyle \int{\frac{e^{x}}{1+e^{x}}\cdot dx} = \int{\frac{du}{u}} = \ln{|u|} = \ln{u} +C = \ln{(1+e^{x})}+C$ .

Therefore

$\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx} &= \int{dx} - \int{\frac{e^{x}}{1+e^{x}}\cdot dx}\\ & = x - \ln{(1 + e^{x})}+C\end{aligned}$ .

7 0

3 years ago

The question is in the picture ​

The question is in the picture