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enyata [817]
3 years ago
14

Amery 545 g Blaine 6.1 kg Scott 491 g Rosalinda 621 g Zelda 6.25 kg Students in Mr. Conway’s class have bagged lunches of differ

ent weights, as shown in the table. Which student’s lunch is the heaviest?
Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0

we need to have the same unit to compare  *1000 to convert kg to g

Amery   545 g    

Blaine 6.1 kg = 6100 g

Scott 491 grams

Rosalinda 621 g

Zelda 6.25 kg = 6250 g

Zelda has the heaviest lunch

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Two trials are conducted for an experiment. In Trial A, the measured value is 240, while the actual value is 200. In Trial B, th
Zepler [3.9K]

Answer:

A is the answer 456% and 512%

Step-by-step explanation:

Percent Errors

Trial A

Trial B

Measured Value

240

195

Actual Value

200

240

Percent Error

​?

​?

Complete the table.

Percent Errors

Trial A

Trial B

Measured Value

240

195

Actual Value

200

240

Percent Error

440440​%

435435​%

5 0
2 years ago
The test statistic of zequals2.32 is obtained when testing the claim that pgreater than0.3. a. Identify the hypothesis test as b
Sonja [21]

Answer:

a) We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.3  

Alternative hypothesis:p > 0.3  

Right tailed test

b) p_v =P(z>2.32)=0.0102  

c) So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

Step-by-step explanation:

Part a: Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.3  

Alternative hypothesis:p > 0.3  

Right tailed test

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

For this case the statistic is given by z_{calc}= 2.32

Part b: Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.32)=0.0102  

Part c

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

6 0
3 years ago
HELP RIGHT AWAY IF YOU SEE
fenix001 [56]

Answer:

I would say A

Step-by-step explanation:

7 0
3 years ago
Malachi bought a new fishing rod. The regular price of the fishing rod was $125.99. He bought it on sale with a 15% discount. Sa
Volgvan

If the discount is 15 percent, he still pays (100-15) or 85%

125.99 * 85%

125.99 * .85 = 107.09  is the price he pays for the rod

107.09 * .03 =3.21 is the sales tax

107.09+3.21=110.30 is the price of the rod with the discount and the tax

8 0
3 years ago
In California in 2000, the ballot included an initiative to add "none of the above" to the list of options in all candidate race
sveticcg [70]

Answer:

No, because the sample was randomly selected.

Step-by-step explanation:

In this example, the main element that we need to focus on is the way in which the sample was determined. We learn that the sample was taken in California with 1000 people. However, this sample was random, and the survey was conducted in both English and Spanish. The fact that this was a random sample means that it is representative of the population. The size of the population does not affect the accuracy of a random sample.

4 0
3 years ago
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