Hey Katie
4^2x+3 = 1
We need to solve for x
log(4^2x+3) = log (1)
Now take log of
(2x +3) * log (4) = log (1)
2x + 3 = log(1)/log(4)
2x + 3 = 0
2x = 0 - 3
2x = -3
x = -3/2
I hope that's help !
You can say that the slope is negative. A line on a graph that goes from the upper left corner to the bottom right is a negative slope.
It is b
Hope That this helps
a) Since ∠FGI is bisected, that means <em>∠FGH and ∠HGI are congruent</em>.
Therefore, <em>5x - 3 = 6x - 8</em>
x to one side: 6x - 5x = -3 + 8
Subtract: x = 5
Plug in: m∠FGH = 5(5) - 3
Simplify: 25 - 3 = 22
m∠FGH = 22°
b) Since ∠FGH is congruent to ∠HGI, m∠FGH = m∠HGI.
Through substitution, m∠HGI = 22°
c) ∠FGI is ∠FGH and ∠HGI combined, so m∠FGI = m∠FGH + m∠HGI
Substitute: m∠FGI = 22° + 22°
Add: m∠FGI = 44°
