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cricket20 [7]
2 years ago
7

Mary has 20 biscuits in a tin there are 11 plain biscuits 7chocolate biscuits 2 currant biscuits sue takes at random 2 biscuits

from the tin work out the probability that the 2 biscuits were not the same type?
Mathematics
1 answer:
stealth61 [152]2 years ago
7 0
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Make "a" the subject of:
slamgirl [31]

Answer:

a=m-x^2/k^2

Step-by-step explanation:

(k^2(m-a)) /x=x

K^2(m-a)=x^2

m-a=x^2/k^2

a=m-x^2/k^2

7 0
3 years ago
Find the value of the unknown
tatiyna
The correct answer is 66.
7 0
2 years ago
What is x? <br>1. 2.7( 5.1x + 4.9) = 3.2x + 28.9 <br><br><br>2. 5(11x - 18) = 3(2x + 7)
tatyana61 [14]

Answer:

1. x≈1.4825

2. x≈2.26531

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
(m3 -15m2+49m-5) ÷(m-5) is what
Sergio [31]
m^2-10m-1- \frac{10}{m-5}
                       or
\frac{m^3-15m^2+49m-5}{m-5}

Hope this helps!!

4 0
3 years ago
3. Samuel tiene 11 cajas con mosaicos cuadrados de 20 cm por
mihalych1998 [28]

Answer:

Primero veamos el área de la pared, es decir, el área total que Samuel debe cubrir.

La pared es de 3m por 2m.

Entonces el area es:

A = 3m*¨2m = 6m^2.

Ahora veamos los mosaicos.

Cada mosaico es un cuadrado de 20cm por 20cm.

El primer paso sería cambiar las unidades para tener metros aca también.

1cm = 0.01m

entonces.

20cm = 20*0.01m = 0.2m.

Entonces cada mosaico es:

0.2m por 0.2m

El área de cada mosaico es:

a = 0.2m*0.2m = 0.04m^2.

En una caja de mosaicos hay 14 mosaicos, entonces con una caja Samuel puede cubrir 14 veces a, o:

14*0.04m^2 = 0.56m^2.

Y Samuel tiene 11 cajas, entonces tenemos 11 veces lo de arriba:

11*0.56m^2 = 6.16m^2.

Y el área de la pared es 6m^2.

6.16m^2 > 6m^2

Entonces con las 11 cajas de mosaicos podemos cubrir completamente esa pared, y vamos a tener algunos mosaicos sobrantes.

Entonces Samuel no debe comprar mas cajas.

6 0
3 years ago
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