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schepotkina [342]
3 years ago
7

How many cashews are in one serving

Mathematics
1 answer:
notsponge [240]3 years ago
6 0
16 to 18 cashews per serving
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According to the synthetic division below, which of the following statements are true?
kykrilka [37]

Answer:

Options (A) and (D)

Step-by-step explanation:

We can write the given division as,

\frac{2x^2+6x-8}{x+5}=2x-4+\frac{12}{x+5}

Option (A)

When (2x² + 6x - 8) is divided (x + 5), the remainder is 12.

True.

Option (B)

When (2x² + 6x - 8) is divided (x - 5), the remainder is 12.

False.

Option (C)

When x = 5,

2x² + 6x - 8 = 12

2(5)² + 6(5) - 8 = 50 + 30 - 8

                        = 72

False.

Option (D)

When x = -5,

2(-5)² + 6(-5) - 8 = 50 - 30 - 8

                          = 12

True.

Option (E)

(x - 5) is a factor of 2x² + 6x - 8

If (x - 5) is a factor value of 2x² + 6x - 8 should be zero.

False.

Option (F)

(x + 5) is a factor of 2x² + 6x - 8

If (x + 5) is a factor then by substituting x = -5 in the expression value should be zero.

But the value is 12.

False.

5 0
3 years ago
Please help me asapppppppppppppppppppppp :)))))))))))))))))))
Reptile [31]

Answer: X is 15. N is 100

6 0
3 years ago
FAST!!!NEED HELP!!!!
kipiarov [429]

Answer:that is one by on and the answer is 546$ 638

Step-by-step explanation:

7 0
4 years ago
Six measurements were made of the magnesium ion concentration (in parts per million, or ppm) in a city's municipal water supply,
myrzilka [38]

Answer:

163.83-4.03\frac{20.094}{\sqrt{6}}=130.77    

163.83+4.03\frac{20.094}{\sqrt{6}}=196.89    

So on this case the 99% confidence interval would be given by (130.77;196.89)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: 175 177 175 180 138 138

We can calculate the mean and the deviation from these data with the following formulas:

\bar X= \frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=163.83 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=20.093 represent the sample standard deviation

n=6 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=6-1=5

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,5)".And we see that t_{\alpha/2}=4.03

Now we have everything in order to replace into formula (1):

163.83-4.03\frac{20.094}{\sqrt{6}}=130.77    

163.83+4.03\frac{20.094}{\sqrt{6}}=196.89    

So on this case the 99% confidence interval would be given by (130.77;196.89)    

7 0
3 years ago
Help me please and thank you
Leviafan [203]

Answer:

Give a picture if you want help/ write the problem

Step-by-step explanation:

8 0
3 years ago
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