6^5 = 6•6•6•6•6
x^7 = x•x•x•x•x•x•x
x^5 = x•x•x•x•x
5^6 = 5•5•5•5•5•5
4 1/2 = 9/2
8 1/4 = 33/4
1/3 x 9/2 = 3/2
1/3 x 33/4 = 33/12
Answer:
Step-by-step explanation:
From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .
So; as each place is fitted with either 0 or 1

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0
Now;
if a 0 bit and a 1 bit are equally likely
The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:
; 
