Halp aspp<br><br><br>give brialest

I need to know the answer as soon as possible.

Paladinen [302]

Answer:

The answer is C. 33y

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Hal bought a guitar for $117.05 and a set of drums for $252.80. What was the total cost of his purchase?

sp2606 [1]

Answer:

369.85

Step-by-step explanation:

Hope it helps!!!!

5 0

3 years ago

What is the unit rate of c=24m

bezimeni [28]

Answer: look it up

Step-by-step explanation:

8 0

3 years ago

Which type of data would be best displayed in a box plot

Mashcka [7]

The type of data that would be best displayed in a box plot is the number of votes received by each of four candidate.

A box plot is used to study the distribution and level of a set of scores. The scores are distributed into 4 groups. Each group has a value of 25%

The whiskers represent the minimum and maximum scores. On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median. The third line on the box represents the upper (third) quartile.

To learn more about box plots, please check: brainly.com/question/27215146

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8 0

2 years ago

My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the

AVprozaik [17]

Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: