HELP!!! I have to get this done by 11:59pm TONIGHT, please help!<br> Here is the problem.

What is the missing value in the table below?

iVinArrow [24]

A geometric series is the collection of an unlimited number of terms with a fixed ratio between them. The missing value in the table below is 343. The correct option is A.

<h3>What is geometrical series?</h3>

A geometric series is the collection of an unlimited number of terms with a fixed ratio between them.

The given table if closely observed forms a geometric progression, this is because the value of the dependent variable, y is increasing by a common ratio. The common ratio in the table is,

Common ratio = y₂/y₁ = 1/(1/7) = 7

Now, for any geometric progression, the value of the nth term is given as,

Tₙ = a₁ (r)⁽ⁿ⁻¹⁾

where a₁ is the first term of the geometric progression and r is the common ratio. Therefore, the nth term of the series is,

T = a₁ (r)⁽ⁿ⁻¹⁾

Tₙ = (1/7) (7)⁽ⁿ⁻¹⁾

y = (1/7)(7)⁽ˣ⁻¹⁾

Now, the value of the y when the value of x is 5 is,

y = (1/7)(7)⁽ˣ⁻¹⁾

y = (1/7)(7)⁽⁵⁻¹⁾

y = (1/7)(7)⁴

y = (1/7) × 2401

y = 343

Hence, the missing value in the table below is 343.

Learn more about Geometrical Series here:

brainly.com/question/4617980

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8 0

2 years ago

I'm.not understanding this at all please help

alekssr [168]

Http://rss2search.com/nohost.php?url=www.edhelperblig.com/cgi-bin/socstud.cgi

6 0

3 years ago

What is the equation of the graph ?

ZanzabumX [31]

Answer:

what graph

Step-by-step explanation:

4 0

3 years ago

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. Consider the sample m

love history [14]

Answer:

a) The expected value of the sample mean weight is 20.4 pounds.

b)The standard deviation of the sample mean weight is 0.123.

c) There is a 14.46% probability the sample mean weight will be less than 20.27.

d) This value is $c = 20.6153$ .

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. This means that $\mu = 20.4, \sigma = 1.23$

Consider the sample mean weight of 100 watermelons of this variety. This means that $n = 100$ .

a. What is the expected value of the sample mean weight? Give an exact answer.

By the Central Limit Theorem, it is the same as the mean of the population. So the expected value of the sample mean weight is 20.4 pounds.

b. What is the standard deviation of the sample mean weight? Give your answer to four decimal places.

By the Central Limit Theorem, that is:

$s = \frac{\sigma}{\sqrt{n}} = \frac{1.23}{\sqrt{100}} = 0.123$

The standard deviation of the sample mean weight is 0.123.

c. What is the approximate probability the sample mean weight will be less than 20.27?

This is the pvalue of Z when $X = 20.27$ .

Since we are working with the sample mean, we use $s$ instead of $\sigma$ in the Z score formula

$Z = \frac{X - \mu}{s}$

$Z = \frac{20.27 - 20.4}{0.123}$

$Z = -1.06$

$Z = -1.06$ has a pvalue of 0.1446.

This means that there is a 14.46% probability the sample mean weight will be less than 20.27.

d. What is the value c such that the approximate probability the sample mean will be less than c is 0.96?

This is the value of $X = c$ that is in the 96th percentile, that is, it's Z score has a pvalue 0.96.

So we use $Z = 1.75$

$Z = \frac{X - \mu}{s}$

$1.75 = \frac{c - 20.4}{0.123}$

$c - 20.4 = 0.123*1.75$

$c = 20.6153$

This value is $c = 20.6153$ .

6 0

3 years ago

Y=Mx+b and to find the slope

Grace [21]

M is the slope of the equation.

Hope this helps!

5 0

3 years ago

HELP!!! I have to get this done by 11:59pm TONIGHT, please help! Here is the problem.