Answer:
good luck
Step-by-step explanation:
Answer:
Arnold descended a distance of 5,250 ft after his parachute opened
Step-by-step explanation:
Here in this question, we want to know the distance Arnold descended after his parachute opened.
Mathematically, we know that distance = speed * time
In this case;
The speed is the rate at which he descended = 70 ft per second
Now the time is 1 minute and 15 seconds; since 1 minute is 60 seconds, then 1 minute and 15 seconds is 60 + 15 = 75 seconds
So what we are saying is he descended at a rate of 70 ft per second for 75 seconds
Thus, his distance of descent will be 70 ft per second * 75 seconds = 5,250 ft
let x = orginal price of the shorts
$21 = x(100%-20%) * 1.05
$21 = x(80%) * 1.05
$21 = 0.8x * 1.05
Subtract 1.05 from both sides
$19.95 = 0.8x
Divide 0.8 from both sides
$24.9375 = x
So the orginal price of the shorts are about $24.94
Answer:
8x + 11= 315
Step-by-step explanation:
Let x = the number of students in a bus
There are 8 buses
8x is the number of students in buses
There are 11 students in cars
Add this together to get all the students, which is 315
8x + 11= 315
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
