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3 years ago

12

Someone help me with these problems ASAP

1 answer:

Komok [63]3 years ago

4 0

2x^4 + x^3 − 8x^2 − 4x
= x ∙ (2x^3 + x^2 − 8x − 4)
= x ∙ (x^2 ∙ (2x + 1) − 4 ∙ (2x + 1))
= x ∙ (x^2 − 4) ∙ (2x + 1)
= x ∙ (x − 2) ∙ (x + 2) ∙ (2x + 1)

Thus the roots are:
x ∙ (x − 2) ∙ (x + 2) ∙ (2x + 1) = 0
⇒ [x = 0] or [x − 2 = 0] or [x + 2 = 0] or [2x + 1 = 0]
⇒ [x = 0] or [x = 2] or [x = −2] or [x = − 1/2]

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Finding Hypotenuse Lengths. Find the length of the hypotenuse.

ioda

Answer:

11) $\frac{3\sqrt{5}}{2}$

12) $4\sqrt{5}$

13) $22$

14) $18$

15) $2$

16) $24\sqrt{3}$

Step-by-step explanation:

For these problems I used the pythagorean theorem: $a^{2}+ b^{2}= c^{2}$ and SOHCAHTOA

Sin = $\frac{opposite}{hypotenuse}$

Cos = $\frac{adjacent}{hypotenuse}$

Tan = $\frac{opposite}{hypotenuse}$

11)

First find the length of the bottom side by using Cos

$cos(60)=\frac{x}{3}$

$3(cos(60))=x$

$1.5=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$3^{2}+ 1.5^{2}= c^{2}$

$9+2.25=c^{2}$

$\sqrt{11.25}=\sqrt{c^{2}}$

$\frac{3\sqrt{5}}{2}$

12)

Find the length of the bottom side using Cos

$cos(60)=\frac{x}{8}$

$8(cos(60))=x$

$4=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$8^{2}+ 4^{2}= c^{2}$

$64+16=c^{2}$

$\sqrt{80} =\sqrt{c^{2} }$

$4\sqrt{5}$

13)

Find the length of the other side by using Tan

$tan(30)=\frac{x}{11\sqrt{3} }$

$11\sqrt{3}* (tan(30)=x$

$11=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$(11\sqrt{3}) ^{2}+ 11^{2}= c^{2}$

$363+121=c^{2}$

$\sqrt{484} =\sqrt{c^{2}}$

$22$

14)

(This is probably an easier way to do these problems)

Find the hypotenuse by using Cos ( $\frac{adjacent}{hypotenuse}$ )

$cos(60)=\frac{9}{x}$

$cos(60)x=9$

$x=\frac{9}{cos(60)}$

$x=18$

15)

Find the hypotenuse using Sin ( $\frac{opposite}{hypotenuse}$ )

$sin(30)=\frac{1}{x}$

$sin(30)x=1\\x=\frac{1}{sin(x)}$

$x=2$

16)

Find the hypotenuse using Cos ( $\frac{adjacent}{hypotenuse}$ )

$cos(60)=\frac{12\sqrt{3} }{x}$

$cos(60)x=12\sqrt{3}$

$x=\frac{12\sqrt{3} }{cos(60)}$

$x=24\sqrt{3}$

5 0

4 years ago

Find the solution of this system of equations <br> 10x-7y=-1<br> -2x-7=-25

kirill [66]

-13,4, - 9/2 is the answer :)

3 0

3 years ago

Help please it’s due today show work :)

Norma-Jean [14]

Answer:

Step-by-step explanation:

7 hours ago I gave you the answer on this question, my dear!!

4 0

3 years ago

2x - 3y = -5 4x – 4y = - 4 Is (2,3) a solution of the system? Choose 1 answer: А Yes B No

Black_prince [1.1K]

Answer:yes

Step-by-step explanation: it just is

7 0

3 years ago

Which of the three following graphs display the same data?

Zepler [3.9K]

Answer:

B. I and III

Step-by-step explanation:

I and III both have the same data:

March, 73

April 74

May 78

June 84

July 75

II has different data

March 71

April 72

May 85

June 90

July 60

Since I and III have the exact same data, choice B is the best answer

Hope this helps! :)

3 0

3 years ago

Read 2 more answers