The 3rd significant figure is 8 so we add 1 to the 2nd sig fig
answer is 2700
Let w= the length of the side perpendicular to the barn
300-2w= length of the side parallel to the barn
A=w(300-2w)
A=-2w^2+300w
The formula for the w-value of maximum is:
=-b/2a
thus our value will be:
300/4
=75
and
300-2(75)
=150
thus the dimensions to maximize the area is 75 by 150
Answer:
c.
Step-by-step explanation:
can i have brainliest
Answer:
10 students would spend $30.
Step-by-step explanation:
In order to find this, start by looking for the cost per student. We can do this by dividing the overall cost by the number of students.
$12/4 students = $3 per student.
Now we take that unit rate and multiply by the new number of students.
$3 * 10 students = $30 total spent.
