Answer:
<u><em>4 : </em></u> Coordinate of Q = ![(\frac{1}{5} ,\frac{-12}{5} )](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B5%7D%20%2C%5Cfrac%7B-12%7D%7B5%7D%20%29)
<em><u>5 : </u></em> Coordinate of point A = (-2,-2)
Explanation :
4) Given the points M(-3, -4) and T(5,0)
x₁= -3, y₁ = -4 and
x₂ = 5, y₂ = 0
m = 2, n = 1
Now apply the section formula,
{(mx₂+nx₁)/(m+n) , (my₂+ny₁)/(m+n)}
Coordinate of point Q = ![(\frac{1}{5} ,\frac{-12}{5} )](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B5%7D%20%2C%5Cfrac%7B-12%7D%7B5%7D%20%29)
5) AB:BC = 3:4
A = (x,y), end point
B = (4, 1)
C = (12, 5) end point
So, m = 3 & n = 4
x₁ = x , y₁ = y , x₂=12 & y₂ = 5
Apply section formula we get
4 = (36+4x)/7 & 1 = (15 + 4y)/7
28= 36 + 4x 7 = 4y + 15
4x =-8 4y =-8
x = -2 y = -2
Answer:
The rate would be: 4:20 and the unit rate would be 1:5.
Step-by-step explanation:
The 2 angles add up to 90 degrees so
x + y = 90, also:-
x - y = 72 (given)
adding the 2 equations:-
2x = 162
x = 81
and therefore
y + 81 = 90
y = 9
Answer the 2 angles are 81 and 9 degrees
As I understand from the given above, each box when empty weighs 5-2 kg or 3 kg. To determine the total weight of Michael's boxes when empty, we just have to multiply 3 kg by 5. This gives us an answer of 15 kg. Thus, the total mass of Michael's boxes is 15 kg.
Do "42 + 12" Since 7 x 6 is 42 and 4 x 3 is 12.