Question:
The cost of 12 kg sugar is $240 what will be the cost of 3 kg sugar.
Given:
- Cost of 12 kg sugar = $240
To find?
Answer :
<u>To find </u><u>c</u><u>o</u><u>s</u><u>t</u><u> </u><u>of</u><u> </u><u>3kg sugar first we have to find cost of 1 kg sugar</u><u>.</u>
- Cost of 1 kg sugar = Cost of total no. of sugar ÷Total sugar
- Cost of 1 kg sugar = $240/12
- Cost of 1 kg sugar = $20
<u>Now Let's find cost of 3 kg sugar</u>
Cost of 3kg sugar = total no of sugar ×Cost of 1 kg sugar
Cost of 3kg sugar = 3×$20
Cost of 3kg sugar = $60
1,050,200
The number between 1 and 10: 1
The power of 10: 6
The number in scientific notation: 1.05^6 or 1.050200^6
34,600
The number between 1 and 10: 3
The power of 10: 4
The number in scientific notation: 3.46^4
Answer:
36894
Step-by-step explanation:
hope it helps
-9-8(1+4h) = -17. We need to solve for h.
First, use the distributive property for 8(1+4h):
8(1+4h) = 8*1 + 8*4h = 8 + 32h
So -9-8(1+4h) = -17
-9 - (8+32h) = -17
-9 - 8 - 32h = -17
-17 - 32h = - 17
Add 17 on both sides to have the variables on a side and the numbers on the other:
-17 - 32h + 17 = -17 + 17
-32h = 0
divide both sides by -32 to get the variable h alone and its value on the other side:
(-32h)/-32 = 0/-32
h = 0.
So -9-8(1+4h) = -17 for h = 0.
You can recheck your answer (very important):
-9 - 8(1+4h) = -9 -8(1+4*0) = -9 - 8(1+0) = -9-8*1 = -9-8 = -17
The answer has been approved.
Hope this Helps! :)
Answer:
It is the secon option ∆TRS ≈ ∆TPQ ; SAS
Step-by-step explanation: angle t is equal to angle t because it is the same angle
line TR divided by line TP is equal to line TS divided by TQ
