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Sophie [7]
2 years ago
6

Calvin works at smokin sally’s barbecue restaurant and keeps track of the numbers of customers who visit the restaurant over a f

our-day period..
If caliber made an average tip of $1.25 per customer, how much money did Calvin make in tips from Thursday to Sunday?
Mathematics
1 answer:
saul85 [17]2 years ago
5 0

Answer:

Step-by-step explanation:

Dbbdhdbjsbsjsbsbns

You might be interested in
Name the ordered pair for the point. A​
miv72 [106K]

Answer:

point A is (-1.5, 1.5)

Step-by-step explanation:

Hope This Helps!

4 0
3 years ago
How many days between 09/26/16 and 10/04/2016?
KonstantinChe [14]
7 days between them.  27, 28, 29 , 30 , 1, 2, 3
6 0
3 years ago
The total surface area of this cuboid is 112cm squared find the value of x
Liono4ka [1.6K]

Answer:

The height of cuboid is 3 cm

Step-by-step explanation:

Total surface area of cuboid  = 2lb+2bh+2hl

Length of cuboid = 10 cm

Width of cuboid = 2 cm

Let the height be x

Total surface area of cuboid  = 2(10)(2)+2(2)(x)+2(x)(10)

Total surface area of this cuboid is 112 cm squared

 2(10)(2)+2(2)(x)+2(x)(10)=112

40+4x+20x=112

40+24x=112

24x=112-40

24x=72

x=\frac{72}{24}

x=3

Hence the height of cuboid is 3 cm

5 0
2 years ago
Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x
BaLLatris [955]

Answer:

The area of the region is 25,351 units^2.

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em>f<em> is a continuous function on </em>[a,b]<em>, then</em>

                                   \int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) |  {_a^b}

where F is an antiderivative of f.

A function F is an antiderivative of the function f if

                                                    F^{'}(x)=f(x)

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x + 15 and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx

\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2

3 0
2 years ago
3x^2-14x=5<br> Show work too
NemiM [27]

Move all terms to one sides

3x^2 - 14x - 5 = 0

Split the second term in 3x^2 - 14x - 5 into two terms

3x^2 + x - 15x - 5 = 0

Factor out the common terms in the first two terms, then in the last two terms;

x(3x + 1) - 5(3x + 1) = 0

Factor out the common term 3x + 1

(3x + 1)(x - 5) = 0

Solve for x;

<u>x = -1/3, 5</u>

8 0
3 years ago
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