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Deffense [45]
2 years ago
5

A carpenter worked 10 weeks on a particular job, 51/2 days per week and 7 3/4 hours per day. How many hours did the carpenter wo

rk on the job?​
Mathematics
1 answer:
Luden [163]2 years ago
5 0

Answer:

= 426 1/4 hr.

Step-by-step explanation:

5 1/2 = 5.5 Days in a week

7 3/4 = 7.75 hr. Per Day

Total hours in a week = 5.5 × 7.75 = 42.625 hr in a week

In 10 weeks = 42.625 × 10 = 426.25 hr.

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Answer:

g(x) = (x-2)^2 -2

If we compare this function with the vertex form we see that:

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So then the vertex would be (h,k)=(2,-2)

And since the value for a is positive we know that the parabola open upward. We don't have a maximum defined since open upwards and the minimum point correspond to the vertex on this case (2,-2).

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If we compare this function with the vertex form we see that:

a=-1, h =-4, k = 2

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Step-by-step explanation:

We need to remember that the standard form for a parabola is given by the following equation:

y = ax^2 + bx +c

And the vertex form is given by this formula:

y = a(x-h)^2 +k

And we want to find the vertex and if we have a maximum or minimum for each function. Let's begin with g(x)

g(x) = (x-2)^2 -2

If we compare this function with the vertex form we see that:

a = 1, h =2, k =-2

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And since the value for a is positive we know that the parabola open upward. We don't have a maximum defined since open upwards and the minimum point correspond to the vertex on this case (2,-2).

For the function f(x) we assume that we have the following equation:

f(x)= -(x+4)^2 +2

If we compare this function with the vertex form we see that:

a=-1, h =-4, k = 2

And since the value for a is negative we know that the parabola open downward. We don't have a minimum defined since open downwards and the maximum point correspond to the vertex on this case (-4,2).

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