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Lisa [10]
3 years ago
7

X(x+5)+6(x+5)=(x+5)(?) help

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

x = -25/12 or x = -0.2

Step-by-step explanation:

x(x+5)+6(x+5)=(x+5)

Distribute

x^2 + 5x + 6x + 30 = x + 5

Combine

x^2 + 11x + 30 = x + 5

Subtract 1x from both sides

x^2 + 10x + 30 = 5

Subtract 30 from both sides

12x = -25

Divide 12 on both sides

x = -25/12 or -0.2

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Ten times a number is fifty
Rashid [163]

Answer:

5

Step-by-step explanation:

if you multiply 10 and 5, you will get 50

7 0
3 years ago
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Can someone please help me?
VikaD [51]

Answer:

The answer is 27

Step-by-step explanation:

The reason being, you can solve this 2 ways.

1) Combine like terms, 7a-4a = 3a.

Now just substitute (a=9) into 3a.

3 * (9) = 27.

2) Or just substitute a = 9 into the original expression.

7 * (9) - 4 * (9)

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4 0
2 years ago
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4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

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• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
2 years ago
At the movie theatre, child admission is $5.20 and adult admission is $8.60. On Sunday, 132 tickets were sold for a total sales
xxMikexx [17]

Answer:

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Step-by-step explanation:

Let x be the number of sold children's tickets and let y be the number of adult tickets sold, then we can pose the following equations.

x + y = 132   (i) Because 132 tickets were sold in total

5.20x + 8.60y = 931.20   (ii)   because the total of $ obtained by sales was 931.20.

We must clear x. Then we substitute (i) in (ii)

5.20x +8.60(132-x) = 931.20

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x = 60

60 tickets for children were sold

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3 years ago
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choli [55]
As it a lowest one so you will have to double it It is 16:64
6 0
3 years ago
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