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Svetllana [295]
3 years ago
7

Which expression is equivalent to mc015-1.j mc015-2.j mc015-3.j mc015-4.j mc015-5.j

Mathematics
2 answers:
jonny [76]3 years ago
8 0

Answer:

B mc015-3.j

Step-by-step explanation:

hope this helps!

seropon [69]3 years ago
7 0

Answer:

2

Step-by-step explanation:

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How to turn an improper fraction into a mixed number witgout remainder?
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1. Multiply the whole number by the fraction's denominator
2. Add that to the numerator.
3. Then write the result on top of the numerator.
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4 years ago
I need help with question two please, it’s due tomorrow first thing so kinda need to get it done
oksano4ka [1.4K]
The third option: y = kx^2
4 0
2 years ago
Consider a square whose size varies. Let s s represent the side length of the square (in cm) and let P P represent the perimeter
chubhunter [2.5K]

Answer:

P = 4s

Step-by-step explanation:

The perimeter of a geometric shape is simply the sum of all its sides length. Since the shape in question is a square, which means that all of the four sides have the same length 's', the perimeter can be expressed by:

P = s+s+s+s\\P=4s

For any value of 's', the formula above expresses the perimeter 'P' as a function of 's'

6 0
3 years ago
Solve the following equation for X.<br> 3x – 9 = -33
IceJOKER [234]

Answer:

<h2>-8</h2>

Option D is the right option

solution,

3x - 9 =  - 33 \\ or \: 3x =  - 33 + 9 \\ or \: 3x =  - 24 \\ or \: x =  \frac{ - 24}{3}  \\ x =  - 8

Hope this helps...

Good luck on your assignment..

4 0
3 years ago
Read 2 more answers
. A bridge over a river is built in the shape of a parabolic arch. The bridge has a span of 100 feet. The height of the arch is
katen-ka-za [31]

Answer:

The height of the arch at its center is 250/9 or about 27.78 feet.

Step-by-step explanation:

We can write an equation to model the parabolic arch.

Let the left-most point of the arch be the origin (0, 0).

Since the bridge has a span of 100 feet, the right-most point must be (0, 100).

We can use the factored form of a quadratic:

y=a(x-p)(x-q)

Where <em>p</em> and <em>q</em> are the <em>x-</em>intercepts.

Our <em>x-</em>intercepts are <em>x </em>= 0 and <em>x </em>= 100. Hence:

y=ax(x-100)

At a point 40 feet from the center, the height of the arch is 10 feet.

The center is <em>x</em> = 50. So, a point 40 feet from the center can be either <em>x</em> = 10 or <em>x</em> = 90.

So, for instance, when <em>x</em> = 10, <em>y</em> = 10. Substitute and solve for <em>a: </em>

<em />10=10a(10-100)<em />

So:

\displaystyle a=-\frac{1}{90}

The same value will result if we let <em>x</em> = 90 and <em>y</em> = 10.

Hence, our equation is:

\displaystyle y=-\frac{1}{90}x(x-100)

The height of the arch at its center will be when <em>x</em> = 50. Hence:

y(50)=\displaystyle -\frac{1}{90}(50)((50)-100)=\frac{250}{9}\approx 27.78\text{ feet}

4 0
3 years ago
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