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kakasveta [241]
3 years ago
11

0,5 numero decimal es finito o infinito

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

...........................

Step-by-step explanation:

...........

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If you have 36 ft of fencing what are the area of the different rectangles you could enclose with the fencing?consider only whol
n200080 [17]

The fence you have must fit the perimeter of the rectangle.

With 36 feet of fence, these are the rectangles that you can enclose:

1-ft x 17-ft . . . Area = 17 ft²

2 x 16 . . . Area =  32 ft²
3 x 15 . . . Area =  45 ft²
4 x 14 . . . Area =  56 ft²
5 x 13 . . . Area =  65 ft²
6 x 12 . . . Area =  72 ft²
7 x 11 . . . Area =  77 ft²
8 x 10 . . . Area =  80 ft²
9 x 9 . . . Area =  81 ft²


6 0
4 years ago
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You roll a six-sided die. Find the probability of each event.
kirill [66]

Answer:

The probability of rolling an answer less than 5 is 66.7 percent

Step-by-step explanation:

5 0
3 years ago
Tell whether the lines through the given points are parallel, perpendicular, or neither.
ira [324]

Answer: Line 1: (2, 3) , (4, 12)

m = (12 - 3)/(4 - 2) = 9/2  This is the slope of the line

y = (9/2)x + b

3 = (9/2)(2) + b

3 = 9 + b

b = -6

y = (9/2)x  - 6

 

Line 2: (5, 10) , (14,8)

m = (8 - 10)/(14 - 5) = -2/9

this slope is the opposite sign, and inverse of the first equation's slope.  Therefore, the line is perpendicular.

y = mx + b

8 = (-2/9)(14) + b

8 = -28/9 + b

11.11 = b

y = (-2/9)x + 11.11

Step-by-step explanation: Hope this helps :)

7 0
2 years ago
Which scenario could NOT be described by the following graph?
beks73 [17]

Answer:

D. the total distance a vehicle travels as it goes up a hill and then maintains a constant rate of speed at the top.

even if the distance increases the graph should rise up.

5 0
3 years ago
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The volume
Sedaia [141]
\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
&&  y={{ k }}x
\end{array}\\ \quad \\


and also

\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
&&y=\cfrac{{{  k}}}{x}
\end{array}


now, we know that V varies directly to T and inversely to P simultaneously
thus\bf V=T\cdot \cfrac{k}{P}

so     \bf V=T\cdot \cfrac{k}{P}\qquad 
\begin{cases}
V=42\\
T=84\\
P=8
\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k
\\\\\\
V=\cfrac{4T}{P}\qquad now\quad 
\begin{cases}
V=74\\
P=10
\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T
7 0
3 years ago
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