#1 <span><span><span>815</span>+<span>425</span></span>+<span>3310</span></span><span>=<span>27910</span></span><span>(Decimal: 27.9)
#2</span><span><span><span>2110</span>+<span>127</span></span>+<span>4910</span></span><span>=<span>617</span></span><span>(Decimal: 8.714286)</span>
Answer:
x= 14
Step-by-step explanation:
First (and only) we subtract 17 from both sides :
17 + x - 17 = 31 - 17
x = 31 - 17
x = 14
Hope this helped and have a good day
<u>Answer:</u>
<u>1. A. You allow the passenger to board his flight when the passenger has a weapon.</u>
<u>2. B. You select the passenger for further inspection when the passenger has no weapon.</u>
<u>Explanation:</u>
1. Remember, a Type I error in simple words means that the assumption "the passenger has a weapon" (null hypothesis) is <em>actually true,</em> but the airport security screener <em>incorrectly concluded it is false. </em>In other words, he assumed the passenger had no weapon and allowed the passenger to board his flight <u>when he actually did have one.</u>
<em>2. While, </em><em>a </em><em>Type II error </em><em>means that </em>the assumption "the passenger has a weapon" (null hypothesis) is <em>actually false, </em>but the airport security screener <em>incorrectly concluded it is true. </em>In other words, he assumed the passenger had a weapon and selected the passenger for further inspection <u>when he actually didn't have one.</u>
Answer:
1/3
Step-by-step explanation:
Probability of solving ten problems by Carl
Given
Total number of problems = 20
Number of problems studied by Carl = 15
Number of problems out of the 20 set of problem coming in test is 10
Case I - All ten problems come from the set of known 15 question
10/15 * 10/20 = 1/3