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lisabon 2012 [21]
3 years ago
8

Elliot wrote a computer program that randomly generates a number from 2 to 10. If he runs the program twice, what is the probabi

lity that the number generated both times is a prime number? StartFraction 2 over 15 EndFraction StartFraction 1 over 6 EndFraction StartFraction 16 over 81 EndFraction StartFraction 9 over 20 EndFraction
Mathematics
2 answers:
Vikentia [17]3 years ago
8 0

Answer:

StartFraction 16 over 81 EndFraction

Step-by-step explanation:

There are 4 prime numbers from 2 to 10 (2, 3, 5, 7) and 9 numbers from 2 - 10. Total possibilities: 9 * 9 = 81

Prime possibilities: 4 * 4 = 16

Therefore the answer is 16/81 or StartFraction 16 over 81 EndFraction

Rus_ich [418]3 years ago
3 0

Answer:

16/81

Step-by-step explanation:

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Step-by-step explanation:

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 8x-6y=-96  add to this -4 times the second equation...
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3 years ago
What is 0.42857142857 as a fraction?
inna [77]

Answer:

What is 0.42857142857 as a fraction?

To write 0.42857142857 as a fraction you have to write 0.42857142857 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

0.42857142857 = 0.42857142857/1 = 4.2857142857/10 = 42.857142857/100 = 428.57142857/1000 = 4285.7142857/10000 = 42857.142857/100000 = 428571.42857/1000000 = 4285714.2857/10000000 = 42857142.857/100000000 = 428571428.57/1000000000 = 4285714285.7/10000000000 = 42857142857/100000000000

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0.42857142857 as a fraction equals 42857142857/100000000000

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