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kompoz [17]
3 years ago
7

Solve this fast speed run ​

Mathematics
1 answer:
FrozenT [24]3 years ago
8 0
Volume is 480 cm
surface area is 376
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Solve tan X = 2cot X
vichka [17]
If x = 1 the the answer would be <span>2.01715045524.</span>
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4 years ago
CP is equal to 200 SP is equal to 100 find the profit or loss​
ioda

Answer:

100

Step-by-step explanation:

if SP>CP,

It is profit [SP - CP = Profit]

if CP>SP,

It is loss   [CP - SP = Loss]

Here in the question CP>SP so,

loss = CP - SP

       =200 - 100

       = 100

5 0
3 years ago
Write the equation of the line ?<br><br>y=?<br><br>PLEASE HELP <br><br><br>​
sashaice [31]

Answer:

y=-2/3x -6

Step-by-step explanation:

y=-6 so b=-6

rise/run=-2/3

Put that into an equation of y=mx+b and you get y=-2/3x -6

5 0
3 years ago
Please Need Help Very Badly!!!
kherson [118]

Answer: use a ruler and measure each side multiply by 30 then multiply all of them by each other

hope this helps and if I'm wrong hope you for give me here is some memes

8 0
4 years ago
Read 2 more answers
The table shows the viscosity of an oil as a function of temperature. Identify a quadratic model for the viscosity, given the te
777dan777 [17]

Answer:

The viscosity at 140°C is predicted to be 7.2

Step-by-step explanation:

The function that model the relationship between viscosity and temperature = Quadratic model

The general form of a quadratic equation is y = a·x² + b·x + c

Therefore, we have;

When y = 10.8, x = 110, which gives;

10.8 = a·110² + b·110 + c = 12100·a + 110·b + c

10.8 = 12100·a + 110·b + c

When y =8.2, x = 130

8.2 = a· 130² + b· 130 + c = 16900·a + 130·b + c

8.2 = 16900·a + 130·b + c

When y = 160, x = 5.8

5.8 = a·160² + b·160 + c = 25600·a + 160·b + c

5.8 = 25600·a + 160·b + c

The three equations above can be listed as follows;

10.8 = 12100·a + 110·b + c

8.2 = 16900·a + 130·b + c

5.8 = 25600·a + 160·b + c

Solving using matrices gives;

\begin{bmatrix}12100 & 110 & 1\\ 16900 & 130 & 1\\ 25600 & 160 & 1\end{bmatrix} \begin{bmatrix}a\\ b\\ c\end{bmatrix} = \begin{bmatrix}10.8\\ 8.2\\ 5.8\end{bmatrix}

\begin{bmatrix}a\\ b\\ c\end{bmatrix} = -\dfrac{1}{3000}\begin{bmatrix}3 & -5 & 2\\ -867 & 1350 & -480\\ 62400 & -88000 & 28600\end{vmatrix} \begin{bmatrix}10.8\\ 8.2\\ 5.8\end{bmatrix}

From which we have;

a = 0.001, b = -0.37, c = 39.4

Substituting gives;

y = 0.001·x² - 0.37·x + 39.4

When x = 140

y = 0.962·140² - 0.37·140 + 39.4= 7.2

The viscosity at 140°C = 7.2.

8 0
3 years ago
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