Question

How was this answered? i don't know how, pls. help​

Answer 1

Answer:

see explanation

Step-by-step explanation:

Using $\sqrt{-1}$ = i, then i² = ($\sqrt{-1}$ )² = - 1

and i³ = i² × i = - 1 × i = - i

also

$i^{4}$ = i² × i² = - 1 × - 1 = 1

We can surmise that i raised to any multiple of 4 will equal 1

Given

$i^{35}$ ( note 35 = 32 + 3 and 32 is a multiple of 4 ), thus

= $i^{32+3}$

= 1 × i³ = - i