The measurement should be 130 according to my calculations
You can take the first point as the origin O(0,0) and the second one (-2,0.5) for easier calculations.
Find the slope, m = (y2 - y1)/(x2 - x1)
= -2-0 / -0.5-0 = 2/0.5 = 4
now take (x,y) = (0,0) and m= 4
use the point slope form
(y - y1) = m(x - x1)
(y - 0) = (4)(x - 0) ......taking (x1,y1) = (0,0)
y = 4x + 0 ...... in the form of y = mx + b
I hope I was helpful:)
Answer:
<h3>132°</h3>
Step-by-step explanation:
If line PS has midpoint a Q and ray QR, then line PQS will be a straight line and <PQR + <RQS = 180 (sum of angle on a straight line).
Given
<PQR = 3x-6
<RQS = x+ 2
To get x, we will use the relationship above;
3x-6+x+2 = 180
4x-4 = 180
add 4 to both sides
4x-4+4 = 180+4
4x = 184
x = 184/4
x = 46
Since <PQR = 3x-6, we will substitute the value of x into the formula;
<PQR = 3x-6
<PQR = 3(46)-6
<PQR = 138-6
<PQR = 132°
Hence the size of angle PQR is 132°
