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Ivahew [28]
3 years ago
6

What is y=− 2/9 x+2 written in standard form?

Mathematics
1 answer:
quester [9]3 years ago
8 0

Answer:

2x+9y=18

Step-by-step explanation:

Distribute the denominator

y=-2/9x+2

9y=-2x+2

9y+2x=2

im sorry if this is wrong

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brilliants [131]

Step-by-step explanation:

(x +40)° = 60°

60°- 40°=20°

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7 0
3 years ago
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MATH WORD PROBLEM
Sloan [31]

cost of one regular admission ticket = $ 10

cost of one senior citizen ticket = $ 5

<h3><u>Solution:</u></h3>

Let "r" be the cost of one regular admission ticket

Let "s" be the cost of one senior citizen ticket

Given that,

<em><u>On day 1 you sold 30 Regular Admission tickets and  20 Senior Citizen tickets for a total of $400</u></em>

So we can frame a equation as:

30 Regular Admission tickets x cost of one regular admission ticket + 20 Senior Citizen tickets x cost of one senior citizen ticket = $ 400

30 \times r + 20 \times s = 400

30r + 20s = 400 ----- eqn 1

<em><u>Day two you sell 40 Regular Admission tickets and only 10 Senior  Citizen tickets for a total of $450</u></em>

So we can frame a equation as:

40 Regular Admission tickets x cost of one regular admission ticket + 10 Senior Citizen tickets x cost of one senior citizen ticket = $ 450

40 \times r + 10 \times s = 450

40r + 10s = 450 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "r" and "s"</u></em>

Multiply eqn 2 by 2

80r + 20s = 900 --- eqn 3

Subtract eqn 1 from eqn 3

80r + 20s = 900

30r + 20s = 400

(-) ---------------------

50r = 500

<h3>r = 10</h3>

Substitute r = 10 in eqn 1

30r + 20s = 400

30(10) + 20s = 400

300 + 20s = 400

20s = 100

<h3>s = 5</h3>

<em><u>Thus we have:</u></em>

cost of one regular admission ticket = $ 10

cost of one senior citizen ticket = $ 5

4 0
4 years ago
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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

oh yeah yeah

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4 years ago
Help me solve this please
LuckyWell [14K]

9514 1404 393

Answer:

  shaded/square = (50π cm²)/(400 cm²) = π/8

Step-by-step explanation:

The quarter circle has area ...

  A = (1/4)(πr²) = π/4(20 cm)² = 100π cm²

The half-circle has area ...

  A = (1/2)(πr²) = π/2(10 cm)² = 50π cm²

Then the area of the shaded portion is ...

  shaded = 100π cm² -50π cm² = 50π cm²

__

The area of the square is ...

  A = s² = (20 cm)² = 400 cm²

Then the ratio of interest is ...

  shaded/square = (50π cm²)/(400 cm²) = π/8

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3 years ago
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