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GalinKa [24]
2 years ago
7

A number, n, is multiplied by −0. 7. The product is -1/2. What is the value of n?​

Mathematics
1 answer:
Degger [83]2 years ago
6 0

Step-by-step explanation:

-0.7n = -1/2

-0.7n = -0.5

n = 0.5/0.7

n = 0.715

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Im need help on this question
dimulka [17.4K]
You were right, its the second choice CA=CB+BA
4 0
3 years ago
Write the point-slope equation of the line with the given properties. Solve the equation for y. M= -0.25, (12,7)
-Dominant- [34]

Answer:

y = -0.25x + 10

Step-by-step explanation:

Point-slope form is y - y1 = m (x - x1)

Here, y1 is 7, m is -0.25, and x1 is 12

When you plug these values in, you get y - 7 = -0.25 (x - 12)

Now we have to solve for y.

y - 7 = -0.25 (x - 12)

Distribute

y - 7 = -0.25x + 3

Add 7 to both sides

y = -0.25x + 10

3 0
3 years ago
What is 1/4 of 3200?
Greeley [361]
Answer: 800

Divide 3200 by 4 to get 800.
3 0
3 years ago
Read 2 more answers
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
A black line is longer than a gray line. The gray line is longer than a white line. Is the black line shorter or longer than the
enot [183]
The gray line is longer than the white line.
The black line is longer than the gray line.

White    -------------------------

Gray      ------------------------------------------

Black     --------------------------------------------------------

Answer: The black line is longer than the white line.
4 0
3 years ago
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