Answer:
You can draw three rectangles:
1- 28 * 1.
2- 14*2
3- 7*4
Step-by-step explanation:
We have a total area of 28. If we use only integer numbers, we can find all the divisors of 28. The possible rectangles will be organized with them, taking into account that the product of them, which means the area should be 28.
28 = 1*2*2*7
We can organize them as follows:
R1: 28 = 1*28
R2: 28 = 2*14
R3: 28 = 4*7
Finally, we can conclude that there are only three possibilities
1- 28 by 1.
2- 14 by 2
3- 7 by4
The perimeters will be:
Perimeter 1 = 2x1 + 2x28 = 58
Perimeter 2 = 2x2 + 2x14 = 32
Perimeter 3 = 2x4+2x7 = 22
Answer:
1.)
y = 2x + 5 for x = 1
y = 2(1) + 5
y = 2 + 5
y = 7
2.) The function rule that relates the total cost of the party to the number of children n.
TCP = $60 + $4(n)
3/4 x 12 = 9 in decimal form.
3/4 x 12 = 9/1 in fraction form
The answer is 14 m
<span>In
a 30°-60°-90° triangle, the hypotenuse (c) is twice the length of the shorter
leg (a) which is the opposite to the 30 angle:
</span>
c = 2a
We have c = 28 m
So: 28 = 2a
a = 28 / 2
a = 14 m
Answer:
3x-5> 6x- 14
Step-by-step explanation:
Let the blue ribbons be denoted by the letter x.
Then according to the given condition
3 times the blue ribbons = 3x
Decreased by 5 = 3x-5
is greater than
6 times the blue ribbons = 6x
decreased by 14 = 6x-14
Putting in one line
3x-5> 6x- 14
Solving the inequality
3x-5> 6x- 14
Taking both sides positive as in modulus
14-5 > 6x-3x
9> 3x
9/3 > x
3> x
Again solving for inequality
3x-5> 6x- 14
Taking one side negative that is mod
3x-5> -6x + 14
3x+ 6x > 14+5
9x> 19
x > 19/9
x > 2.11
so x lies between 2 and 3
3 > x > 2.11
Now putting the values for x= 19
3x-5> 6x- 14
57-5> 114-14
52 > 100 False
Now putting the values for x= 3
3x-5> 6x- 14
9-5> 18-14
4>4 False
Now putting the values for x= 2
3x-5> 6x- 14
6-5> 12-14
1> -2 True
There are 2 blue ribbons
