1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Liono4ka [1.6K]
3 years ago
9

If a standard frequency scale is 220 hertz, how many scales is a 1100 hertz frequency?

Mathematics
1 answer:
jenyasd209 [6]3 years ago
7 0

Answer:

5

Step-by-step explanation:

If one standard frequency scale is 220 hertz

Then the number of scales 1100 hertz frequency can be calculated as follows

= 1100/220

= 5

Hence 5 scales are present in 1100 hertz frequency

You might be interested in
How much greater 20 than 12?
Ber [7]
20 is 8 greater than 12. 
6 0
3 years ago
STEAM: The boiling pint of water is affected by changes in elevation. Use the expression of -2A/1000 where a represents the alti
damaskus [11]

Answer:

A) -10°F

Step-by-step explanation:

Given that:

Boiling point of water gets affected when there is a change in the elevation.

Expression to represent the temperature i.e. boiling point w.r.to altitude A is given by the equation:

Temperature in ^\circ F = \frac{-2A}{1000}

Given that, the altitude, A = 5,000 feet

To find:

The number of degrees Farenhite at which the boiling point of water will change.

Solution:

Here, we are given the expression:

Temperature in ^\circ F = \frac{-2A}{1000}

And value of altitude, A = 5,000 feet

Let us put the value of A in the equation and let us find the value of temperature in ^\circ F.

Temperature in ^\circ F =

\frac{-2\times 5000}{1000}\\\Rightarrow -2\times 5\\\Rightarrow \bold{-10^\circ F}

Therefore, the answer is:

A) -10°F

5 0
3 years ago
6.
Daniel [21]
Answer: D opposite angles in all quadrilateral are congruent true
4 0
3 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acce
g100num [7]

Here is the correct format for the question

At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h².Let v(f) be the velocity of the car t hours after 2:00 PM.Then \dfrac{v(1/4)-v(0)}{1/4 -0} = \Box. By the Mean Value Theorem, there is a number c such that 0 < c < \Box  with v'(c) = \Box. Since v'(t)  is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h^2.

Answer:

Step-by-step explanation:

From the information given :

At  2:00 PM ;

a car's speedometer v(0) = 30 mi/h

At 2:15 PM;

a car's speedometer v(1/4) = 50 mi/h

Given that:

v(f) should be the velocity of the car t hours after 2:00 PM

Then \dfrac{v(1/4)-v(0)}{1/4 -0} = \Box will be:

= \dfrac{50-30}{1/4 -0}

= \dfrac{20}{1/4 }

= 20 × 4/1

= 80 mi/h²

By the Mean value theorem; there is a number c such that :

\mathbf{0 < c< \dfrac{1}{4}}     with \mathbf{v'(c) = \dfrac{v(1/4)-v(0)}{1/4 -0}} \mathbf{ = 80 \ mi/h^2}

6 0
3 years ago
Solve the equation loge(13 - x) = 1.
Nat2105 [25]

Answer:

12

Step-by-step explanation:

(13-x)=1

13-x-13=1-13

-x=-12

Divide both sides by -1

3 0
3 years ago
Other questions:
  • The Wall Street Journal reports that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deduction
    6·1 answer
  • Please help on this?
    15·2 answers
  • I need whats in the red rectangle
    8·1 answer
  • A cash register contains only five dollar and ten dollar bills. It contains twice as many five's as ten's and the total amount o
    7·1 answer
  • Solve and graph |-8x|&lt;8 help me lol
    14·1 answer
  • Can someone please help <br><br> Thanks
    12·1 answer
  • Which of the following is the equation of a line in slope-intercept form for a
    12·1 answer
  • Find the measure for angle b
    6·1 answer
  • Which compound inequality can be represented by the graph below?
    10·1 answer
  • 18+6=__+__=__<br> /\<br> 2 4
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!