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maks197457 [2]
2 years ago
6

Determine if this data is an example of a function. (2, -4); (2, 0); (2, 1); (2, 32)

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
5 0
Condimentando ENCANTÁNDOSELA SUSTENTADOR
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An example of financial responsibility is
Maurinko [17]

Answer:

keeping financial records organized

4 0
3 years ago
In scientific notation is 14,200 000 becomes 1.42 x10'5
lyudmila [28]
You are correct with the 1.42 but wrong with the 10^5
Count the digits after the 1, which is 7. So it should be
1.42 x 10^7
6 0
3 years ago
There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
Stacy is making 2, 1/4 batches of cookies. If each batch calls for 1/3 of a cup of sugar, how much sugar will Stacy use?
Luba_88 [7]
Really hope you can read cursive and I really hope this helps! (:

4 0
2 years ago
Read 2 more answers
4cos^2(x)-7cos(x)+3<br> Please help and explain how you did it :)
dangina [55]

I assume you're asked to solve

4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0

Factor the left side:

(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0

Then either

4 cos(<em>x</em>) - 3 = 0   <u>or</u>   cos(<em>x</em>) - 1 = 0

cos(<em>x</em>) = 3/4   <u>or</u>   cos(<em>x</em>) = 1

From the first case, we get

<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em>  <u>or</u>   <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>

and from the second,

<em>x</em> = <em>nπ</em>

where <em>n</em> is any integer.

7 0
2 years ago
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