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2 years ago

What is the slope of the line that passes through the points (6, 7) and (16,22)??? i have been

Mathematics

1 answer:

Stolb23 [73]2 years ago

5 0

Answer:

1.5

Step-by-step explanation:

picture

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A die is rolled. Write each answer as a fraction, decimal, and percent. Show your work.

dalvyx [7]

A. 1/6, .16666666, 16.6666666%
B. 4/6, .64, 64%
C. 5/6, .80, 80%

3 0

3 years ago

Based on the work shown on the right, check all of the possible solutions of the equation.

Mazyrski [523]

Incomplete question. However, here is a similar question attached.

Solve 3x^2 + 17x - 6 = 0.

Based on the work shown to the left, which of these values are possible solutions of the equation? Check all of the boxes that apply

A X=-6

B X=6

C X=-1/3

D X=1/3

E X=0

Answer:

A and D

Step-by-step explanation:

Note that such question requires using completing the square method of solving equations. By using the values X= -6 and X= 1/3 we arrive at a solution.

7 0

3 years ago

1. Write the following sentence as an equation: the product of w and 15 is 165.

Talja [164]

W+15=165
W=165/15
W=11

6 0

2 years ago

A parking lot has two entrances. Cars arrive at Entrance 1 according to a Poisson Probability Distribution at an average of thre

dusya [7]

Answer:

note:

please find the attached solution

7 0

3 years ago

Use Lagrange multipliers to find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Enter the dimens

Dima020 [189]

Answer:

(x,y,z) = (12,12,12) cm

Step-by-step explanation:

The box is assumed to be a closed box.

The surface area of a box of dimension x, y and z is given by

S = 2xy + 2xz + 2yz

We're to minimize this function subject to the constraint that

xyz = 1728

The constraint can be rewritten as

xyz - 1728 = 0

Using Lagrange multiplier, we then write the equation in Lagrange form

Lagrange function = Function - λ(constraint)

where λ = Lagrange factor, which can be a function of x, y and z

L(x,y,z) = 2xy + 2xz + 2yz - λ(xyz - 1728)

We then take the partial derivatives of the Lagrange function with respect to x, y, z and λ. Because these are turning points, each of the partial derivatives is equal to 0.

(∂L/∂x) = 2y + 2z - λyz = 0

λ = (2y + 2z)/yz = (2/z) + (2/y)

(∂L/∂y) = 2x + 2z - λxz = 0

λ = (2x + 2z)/xz = (2/z) + (2/x)

(∂L/∂z) = 2x + 2y - λxy = 0

λ = (2x + 2y)/xy = (2/y) + (2/x)

(∂L/∂λ) = xyz - 1728 = 0

We can then equate the values of λ from the first 3 partial derivatives and solve for the values of x, y and z

(2/z) + (2/y) = (2/z) + (2/x)

(2/y) = (2/x)

y = x

Also,

(2/z) + (2/x) = (2/y) + (2/x)

(2/z) = (2/y)

z = y

Hence, at the point where the box has minimal area,

x = y = z

Putting these into the constraint equation or the solution of the fourth partial derivative,

xyz - 1728 = 0

x³ = 1728

x = 12 cm

x = y = z = 12 cm.

7 0

2 years ago