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3 years ago

I need some help with this.

Mathematics

1 answer:

Alenkasestr [34]3 years ago

7 0

Answer:

b is 16 d is 13

Step-by-step explanation:

ok is a baby girl that can I be happy

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A 20,000 gallon swimming pool contains 5000 gallons of water when a hose is placed in the pool and begins adding water at a rate

nalin [4]

(12,0) and (1250,0) only promblem is on the test since im doing it to there is no place to but (1250,0)

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3 years ago

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2p + 8 = 20-P<br> 2p + 8 + p = 20-p+p<br> 3p + 8 = 20<br><br> what’s the value of p ?

adell [148]

The answer to p is 4

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3 years ago

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The Delhi metro track is 240km long today. Two years ago, it was 200 km long. By what percentage did metro tracl increase in the

aleksley [76]

A percent is 1 in 100 or 1/100

240km-200km=40km it increased 40km in the last 2 years

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4 years ago

Charles has rolled a 6-sided die three times and it landed on 3 each time. What is the probability of getting a 3 on the 4th rol

MA_775_DIABLO [31]

The answer would be D - 1/6

This is because there are six sides to the die and just because he rolled all 3s before it does not mean he has a better chance to roll a 3 now.

Since there is only 1 3 on the six sided die there is a 1/6 chance he would roll a 3.

7 0

3 years ago

Without solving, determine the number of real solutions for each quadratic equation.

masha68 [24]

Answer:

1. x^2 − 4x + 3 = 0

$b^2 -4ac = (-4)^2 -4(1)*(3)= 4 >0$ So we have two real solutions

2. 2n^2 + 7 = −4n + 5

$b^2 -4ac = (4)^2 -4(2)*(2)= 0$ So we just one real solution

3. x − 3x^2 = 5 + 2x − x^2

$b^2 -4ac = (1)^2 -4(2)*(5)= -19$ No real solutions

4. 4x + 7 = x^2 − 5x + 1

$b^2 -4ac = (-9)^2 -4(1)*(-6)= 105 >0$ So we have two real solutions

Step-by-step explanation:

1. x^2 − 4x + 3 = 0

We need to compare this function with the general equation for a quadratic formula given by:

$f(x) = ax^2 + bx + c$

On this case we see that a=1, b = -4 and c =3

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (-4)^2 -4(1)*(3)= 4 >0$ So we have two real solutions

2. 2n^2 + 7 = −4n + 5

We can rewrite the expression like this:

$2n^2 +4n +2$

On this case we see that a=2, b = 4 and c =2

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (4)^2 -4(2)*(2)= 0$ So we just one real solution

3. x − 3x^2 = 5 + 2x − x^2

We can rewrite the expression like this:

$2x^2 +x +5$

On this case we see that a=2, b = 1 and c =5

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (1)^2 -4(2)*(5)= -19$ No real solutions

4. 4x + 7 = x^2 − 5x + 1

We can rewrite the expression like this:

$x^2 -9x -6$

On this case we see that a=1, b = -9 and c =-6

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (-9)^2 -4(1)*(-6)= 105 >0$ So we have two real solutions

8 0

4 years ago