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mr_godi [17]
3 years ago
12

Help please.

atex-formula">

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

r = 8 cm

Step-by-step explanation:

The circumference of a circle is given by

C = 2 * pi *r

50.24 = 2 * (3.14) *r

50.24 = 6.28r

Divide each side by 6.28

50.24/6.28 = r

8 =r

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Answer and Step-by-step explanation:

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7 0
2 years ago
The sum of five times a number, and 1, is equal to four times the number
larisa86 [58]

Answer:

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7 0
3 years ago
Can someone plz help me find the answer to 2x=4 y-16. and 2x-y=-7
telo118 [61]

Answer:

So, y = 2x + 7;

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Step-by-step explanation:


8 0
3 years ago
Solve for x using the quadratic formula. x^2+9x+20=0
il63 [147K]

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Step-by-step explanation:

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3 years ago
Read 2 more answers
In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!
g100num [7]

the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

Step-by-step explanation:

   x^{3} = - 64

   x^{3} +64  = 0

   We can write 64 as  4^{3}

  x^{3} + 4^{3} = 0

  using the identity  ( x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} ) )

we get,

  = (x+4) (x^{2} -x*4+4^{2} )

  = (x+4)(x^{2} -4x+16)    ....................(1)

 solving the quadratic equation  ,

   x^{2} -4x+16 =0

solutions of this quadratic equation can be obtained by

   x=-b +- \sqrt{b^{2}-4ac } /2a

let use y for factors

x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16}  / 2*x^{2}

x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}

x=4+-\sqrt{16-64}/2

x=4+-4\sqrt{3i} /2

<u />x=2+-2\sqrt{3i}    ..................(2)

from the equation 1 we have,

x-4=0

which gives solution x=4

and from equation 2 we got  x=2+-2\sqrt{3i}

so the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

3 0
2 years ago
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