"3 va después de 5 y entre 7 y 12" = "3 goes after 5, and between 7 and 12"
This eliminates A and D (3 is not between 7 and 12 in either choice).
"5 va antes de 12 y entre 7 y 3" = "5 goes after 12, and between 7 and 3"
This eliminates C (5 is not between 7 and 3).
So the correct sequence is B.
Simplify the following:
(6^5/7^3)^2
7^3 = 7×7^2:
(6^5/(7×7^2))^2
7^2 = 49:
(6^5/(7×49))^2
7×49 = 343:
(6^5/343)^2
6^5 = 6×6^4 = 6 (6^2)^2:
((6 (6^2)^2)/343)^2
6^2 = 36:
((6×36^2)/343)^2
| | 3 | 6
× | | 3 | 6
| 2 | 1 | 6
1 | 0 | 8 | 0
1 | 2 | 9 | 6:
((6×1296)/343)^2
6×1296 = 7776:
(7776/343)^2
(7776/343)^2 = 7776^2/343^2:
7776^2/343^2
| | | | 7 | 7 | 7 | 6
× | | | | 7 | 7 | 7 | 6
| | | 4 | 6 | 6 | 5 | 6
| | 5 | 4 | 4 | 3 | 2 | 0
| 5 | 4 | 4 | 3 | 2 | 0 | 0
5 | 4 | 4 | 3 | 2 | 0 | 0 | 0
6 | 0 | 4 | 6 | 6 | 1 | 7 | 6:
60466176/343^2
| | | 3 | 4 | 3
× | | | 3 | 4 | 3
| | 1 | 0 | 2 | 9
| 1 | 3 | 7 | 2 | 0
1 | 0 | 2 | 9 | 0 | 0
1 | 1 | 7 | 6 | 4 | 9:
Answer: 60466176/117649
Answer:
It takes a couple days for checks and deposits to post to your account.
Step-by-step explanation:
Answer:
4L +4W +16 square inches
Step-by-step explanation:
The area of the border is the equivalent of that of a rectangle with a width equal to the width of the border, and a length equal to the length of the midline of the border. That length is the perimeter of the rectangle that is L+2 units long and W+2 units wide.
border midline length = 2((L+2) +(W+2)) = 2L +2W +8
Then the border area is ...
border area = (border width)(border length) = (2)(2L +2W +8)
border area = 4L +4W +16 . . . square inches
_____
You can also figure this as the difference between the area of the rectangle with the border and the area of the rectangle inside the border:
border area = total area - canvas area
= (L+4)(W+4) -LW = LW +4L +4W +16 -LW
= 4L +4W +16 . . . . square inches
