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Serggg [28]
3 years ago
9

–12(x + 3) - 4(5 - 2x) = 20

Mathematics
2 answers:
bekas [8.4K]3 years ago
8 0
-12x -36 -20 +8x = 20
-12x + 8x = 20 + 36 + 20
-4x = 76
x = -19
12345 [234]3 years ago
7 0

Answer:

x = -19

Step-by-step explanation:

1. make parentheses disappeared using distribution law.

- 12x - 36  - 20 + 8x = 20

2. sum up b numbers and x

- 4x - 56 = 20

3. separate x and number to two sides of the equation

- 4x = 76

4. both side divided by -4

x =  - 19

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2 years ago
Name the pair of opposite rays with endpoint N.
Elza [17]

Answer:

<h2>Possible Answers: NA and NX or NM and NC.</h2>

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3 0
3 years ago
What’s the answer to this equation<br> 4x7=(__x5)+(4x2)
motikmotik

Answer:

4

Step-by-step explanation:

4X7 =28

4X2 =8

28-8 =20/5

=4

5 0
3 years ago
I am really lost I need help
jeka57 [31]
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4 0
3 years ago
Read 2 more answers
Find the equation for the plane that contains the line x=−1+3t , y=1+2t, z=2+4t and is perpendicular to the plane containing the
Ivan

Let L be the line given by the vector equation

(-1,1,2) + \lambda(3,2,4) \ , \lambda \in \mathbb{R}.

First, we use the director vectors of the lines L1 and L2 to get the

vector equation of the plane containing them, which we denote by \Pi_1. This is,

\\\\\Pi_1  : (1,-1,5) + \alpha (2,-1,6) + \beta (1,1,-3) \ , \alpha, \beta \in \mathbb{R}\\\\\\

We observe that \vec{N} = (2,-1,6)\times(1,1,-3) = (-3,12,3) \ne (0,0,0). Therefore, the vector equation of \Pi_1 defines a plane and \vec{N} is a normal vector to \Pi_1.

 

Finally, the vector equation for the wanted plane, which we denote by \Pi, is

\Pi : (-1,1,2) + r(3,2,4) + s(-3,12,3), r,s \in \mathbb{R} \ .

Thus, if s = 0, then L \subset \Pi and since \vec{N} is parallel to \Pi, then it is perpendicular to \Pi_1.

8 0
3 years ago
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