PLease answer 1, 2, and 3 so I can be free till december

Someone help me with 12 I don’t understand stand this question someone please help me with work shown

allochka39001 [22]

2x+8+ 120= 180
Combine like terms so 8+120=128

2x+8+ 120= 180
2x+128=180
-128=-128 ( to both side)
2x= 52 You divide now
2x/2= 52/2
x= 26
There is your answer :)

5 0

3 years ago

Inside a square with side length 10, two congruent equilateral triangles are drawn such that they share one side and each has on

Sphinxa [80]

Answer:

5 length

Step-by-step explanation:

The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.

So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.

4 0

3 years ago

Does anyone know what 1+1 is?

hammer [34]

1+1 = 2 that is the answer

6 0

3 years ago

Read 2 more answers

When does expanding and simplifying a(b+c) result in a positive value for ac

TiliK225 [7]

Answer:

Step-by-step explanation:

(ab + bc)(ab + bc)

Simplifying

(ab + bc)(ab + bc)

Multiply (ab + bc) * (ab + bc)

(ab(ab + bc) + bc(ab + bc))

((ab * ab + bc * ab) + bc(ab + bc))

Reorder the terms:

((ab2c + a2b2) + bc(ab + bc))

(ab2c + a2b2 + (ab * bc + bc * bc))

(ab2c + a2b2 + (ab2c + b2c2))

Reorder the terms:

(ab2c + ab2c + a2b2 + b2c2)

Combine like terms: ab2c + ab2c = 2ab2c

(2ab2c + a2b2 + b2c2)

7 0

3 years ago

An athlete jumps vertically at t=0 from the ground and stays in the air for one second before landing on the ground again. The h

lawyer [7]

Answer:

The answer is B

Step-by-step explanation:

I just did the Quick Check, the attachment is the answer, np.

3 0

3 years ago