So there are two triangles here: Smaller one (ADE) and bigger one (ABC) and they both are similar.
So you can use proportions here.
AB / AC = AD / AE
AB = AD + DB = 6 + 1 = 7
AC = AE + 3
AD = 6
So plug in these values:
AB / AC = AD / AE becomes
7 / (AE + 3) = 6 / AE
Now do the cross multiply:
7 AE = 6 (AE + 3)
Now solve for AE:
7AE = 6AE + 18
AE = 18
Answer:
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Answer:
x = 4, TU = 22
Step-by-step explanation:
Given that TS bisects TU at Q , then
TQ = QU , substitute values
5x - 9 = 15 - x ( add x to both sides )
6x - 9 = 15 ( add 9 to both sides )
6x = 24 ( divide both sides by 6 )
x = 4
Thus
TU = 5x - 9 + 15 - x = 4x + 6 = 4(4) + 6 = 16 + 6 = 22
See the attachment for detailed answer
<span>So then R is 1/6 of the way from E to F.
The x distance from E to F is 11- 4=7.
So then the x distance from E is,
Similarly for y,
R:(31/6,22/3)</span>
There are a total of 6 groups.
And each group contains at least 4 students.
So the minimum number of students is:
minimum = 6 * 4 = 24 students
Let us say that x represents the number of students,
hence:
<span>x ≥ 24</span>