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Amiraneli [1.4K]
2 years ago
6

Determine if the sequence is arithmetic. If it is, find the common difference.

Mathematics
1 answer:
ValentinkaMS [17]2 years ago
6 0

Answer:

1) yes--common difference is 3.

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7 × (–3) × (–2)2 = ? <br><br> A. 84<br> B. 48<br> C. –84<br> D. –48
Dahasolnce [82]


7 × (-3) ×(-2)2 =

7 × -3 × -4 = (you have to eliminate all parenthesis in the equation.)

7 × -12 = -84

so your answer would be: C

3 0
3 years ago
Read 2 more answers
Determine the solution to the system of equations graphed below and explain your reasoning in complete sentences.
Anarel [89]

Answer:

  (0, -3)

Step-by-step explanation:

The solution to the system of equations is the point at which they intersect. The problem statement tells you that point is (x, y) = (0, -3).

__

Often, for a system defined using functional notation, we don't care about the value of the function. We only care about the value of x where the functions have the same value. That is ...

  the solution to f(x) = g(x) is x = 0.

3 0
3 years ago
How do I do this because it's really confusing haha
netineya [11]
A = 1.5
B = -1/3
C = -4/3

A is a positive so there is only one possibility
B is in between 0 and -1, so it has to be -1/3
C is below -1 and so its the improper fraction

5 0
3 years ago
Can you help me find t value in this problem?
Eduardwww [97]

we have a maximum at t = 0, where the maximum is y = 30.

We have a minimum at t = -1 and t = 1, where the minimum is y = 20.

<h3>How to find the maximums and minimums?</h3>

These are given by the zeros of the first derivation.

In this case, the function is:

w(t) = 10t^4 - 20t^2 + 30.

The first derivation is:

w'(t) = 4*10t^3 - 2*20t

w'(t) = 40t^3 - 40t

The zeros are:

0 = 40t^3 - 40t

We can rewrite this as:

0 = t*(40t^2 - 40)

So one zero is at t = 0, the other two are given by:

0 = 40t^2 - 40

40/40 = t^2

±√1 = ±1 = t

So we have 3 roots:

t = -1, 0, 1

We can just evaluate the function in these 3 values to see which ones are maximums and minimums.

w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20

w(0) = 10*0^4 - 20*0^2 + 30    = 30

w(1) =  10*(1)^4 - 20*(1)^2 + 30 =  20

So we have a maximum at x = 0, where the maximum is y = 30.

We have a minimum at x = -1 and x = 1, where the minimum is y = 20.

If you want to learn more about maximization, you can read:

brainly.com/question/19819849

6 0
2 years ago
In 2010, a city population was 55,210 and it was declining at a rate of 1.09 each year. What is the best prediction for when the
PSYCHO15rus [73]
48000=55210(1-0.0109)^t
Solve for t
t=12.77 =13 years
2010+13=2023

So the answer is c
5 0
3 years ago
Read 2 more answers
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