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Crank
3 years ago
12

Geometry please help

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0
VXW is 68 degrees

You can use the alternate interior angles theorem to put XVW as 52 degrees and then add 52 and 60 up and subtract from 180 since every triangle has 180 degrees
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You are trying to find the area of a deck that is surrounding a rectangular pool. The length of the deck is 2x + 1 and the width
OverLord2011 [107]

Answer:

6x² + 9x + 2

Step-by-step explanation:

The pool is a square with a side length of 2x.

The area of the pool = length * length = 2x * 2x = 4x²

The area of the deck surrounding the pool has length of 2x + 1 and width of 5x + 2. Therefore:

The area of the deck surrounding the pool = length * width = (2x + 1)(5x + 2) = 10x² + 4x + 5x + 2 = 10x² + 9x + 2

Area of the deck only = area of the deck surrounding the pool - area of pool =  (10x² + 9x + 2) - 4x²

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N^2+16n+60 over 36-n^2
svetoff [14.1K]
Factor
36-n^2 is difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
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factor

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(x+6)(x+10)
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so the equation is
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Step-by-step explanation:

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