Use the greatest common factor to find the least common multiple of 12 and 18. What is the least common multiple of 12 and 18?

HELP HELP PLEASE!! D: Determine the missing side length!! PLEASE NO CAP!!

charle [14.2K]

Answer:

missing side length = 9

Step-by-step explanation:

$c^{2} = a^{2} + b^{2}$

a = 6

b = 7

c = missing side

$c^{2} = 6^{2} + 7^{2}$

$c^{2} = 36 + 49$

$c^{2} = 85$

$\sqrt{c^{2} } = \sqrt{85}$

$c = 9.219 = 9$

5 0

3 years ago

What number is smaller number -5 or -15? Explain your answer. Please help college math basic algebra

Goryan [66]

-15 is the smaller number because the further you go into the negatives like -30, -47, -52; youre getting further away from 0 and after 0 are positive numbers so -15 would be the smaller number

8 0

2 years ago

Read 2 more answers

Help me out with number 8!!! I’m confused and I need this by tomorrow HELP PLEASE

ivann1987 [24]

We can use elimination for these set of systems.
First, we need to set up our variables.
Belts=b
Hats=h
Now, the situation is 6 belts and 8 hats for $140. The situation after is 9 belts and 6 hats for $132.
Let’s set up our system of equations.
6b+8h=140
9b+6h=132
We need to eliminate a variable. Since b has coefficients of 6 and 9, we can easily eliminate b by multiplying the top equation by 3 and the bottom by -2.
18b+24h=420
-18b-12h=-264
Now let’s add.
12h=156
Let’s divide to get h by itself.
156/12=13=h
So a hat costs $13. We need to put in 13 for one of the equations so we can find the cost of a belt.
9b+6(13)=132
9b+78=132
We need b by itself.
9b=54
54/9=6
Belts are $6
We can also use the first equation to check our answers.
6(6)+8(13)
36+104
140.
So, the price of a belt is $6 while the price of a hat is $13.

3 0

2 years ago

in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru

melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is

n = 200

the proportion is

p = 154/200 = 0.77

Since both np ≥ 10 and n(1-p) ≥ 10

We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant difference.

The approximation would be to a Normal curve with this parameters:

Mean

p = 0.77

Standard deviation

$\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298$

The 90% confidence interval for the proportion would be then

$\bf [0.77-z^*0.0298, 0.77+z^*0.0298]$

where $\bf z^*$ is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval $\bf [-z^*,z^*]$ is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

NORMSINV(0.95) and we get a value of 1.645

The 90% confidence interval for the proportion is then

$\bf [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]$

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

5 0

3 years ago

Increase £2193.67 by 8.5%

HACTEHA [7]

Answer:

£2380.23

Step-by-step explanation:

The increase will be 8.5% of £2193.76 added to £2193.76

That’s

8.5% of £2193.76

8.5% /100% x £2193.76

0.085 x £2193.76

£186.47

Increase = £2193.76 + £186.47

= £2380.23

6 0

3 years ago