AB = ==> distance between the bottom of the plank; and the wall ===> 3 ft.
C ====> 49 degrees
For letter a, to solve for AC:
AC ==> HYPOTENUSE. The angle C is the OPPOSITE side of AB.
use sine :
sin A ===> opposite/hypotenuse
Solve:
sin 49 ====> 3/AC
AC ====> 3 / sin 49
AC ====> 3.96 ft.
For letter b, to solve for BC:
We are now given with the base (3 ft.); and; the hypotenuse (3.96 ft.) so we can use the Pythagorean theorem:
a^2 + b^2 = c^2
Let:
a ===> AB
b ===> BC
c ===> AC
(AB)^2 + (BC)^2 ===> (AC)^2
3^2 + (BC)^2 ===> (3.96)^2
(BC)^2 ===> (3.96)^2 - 3^2
(BC)^2 ===> 6.6816
sqrt (BC)^2 ===> sqrt 6.6816
Answer: BC ===> 2.58 ft.
Hope that helps!!!! : )
We have an equation: ?/45= 24/100
Cross multiply:
100*? = 24*45
⇒ ?= 24*45/100= 10.8
24% out of 45 is 10.8~
The answer is 116%
I hope this helped :))
If A=38x-x^2 then
dA/dx=38-2x
d2A/dx2=-2
Since the acceleration, d2A/dx2 is a constant negative, when velocity, dA/dx=0, it will be an absolute maximum for A(x)
dA/dx=0 only when 38=2x, x=19
A(19)=38(19)-19^2
A(19)=722-361
A(19)=361 ft^2
So the maximum possible area is 361 ft^2
(This will always be true as the maximum possible area enclosed by a given amount of material will always be a perfect square...)
