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sesenic [268]
4 years ago
6

What is the area of a triangle with a base of 74 and a height of 17

Mathematics
1 answer:
alexandr1967 [171]4 years ago
4 0
629 is ur answer to ur question
You might be interested in
What is the distance between the points (-12, 11) and (-18, 17), to the<br> nearest tenth? *
Basile [38]

Answer:

8.5 units

Step-by-step explanation:

The distance between two points is given by

d=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Taking points (-12, 11) and (-18, 17) as the first and second points respectively then

d=\sqrt{(-18--12)^{2}+(17-11)^{2}}

d=\sqrt {36+36}

d=8.48528137423857 units

Rounded off to nearest tenths

d=8.5 units

6 0
3 years ago
Please answer correctly !!!!!! Will mark brainliest answer !!!!!!!!!!
Rasek [7]

Answer:

see below

Step-by-step explanation:

1. 0 = (r + 1)(r + 8)

Using Zero Product Property, r = -1, r = -8

2. h(r) = (r + 1)(r + 8)

         = r² + 9r + 8

         = (r + 9/2)² - 81/4 + 8

         = (r + 4.5)² - 12.25 (Complete the square)

   Vertex: (-4.5, -12.25)

5 0
3 years ago
Could anyone find this?
lina2011 [118]

Answer:

Step-by-step explanation:

Since the squares have areas of 32u^2. The side lengths are

s=\sqrt{32}\\ \\ \text{By the Pythagorean Theorem}\\ \\ x^2=s^2+s^2\\ \\ x^2=32+32\\ \\ x^2=64\\ \\ x=\sqrt{64}\\ \\ x=8

8 0
3 years ago
how many 4 digit numbers n have the property that the 3 digit number obtained by removing the leftmost digit is one ninth of n
Tom [10]

Answer:

  7

Step-by-step explanation:

We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.

__

Let the thousands digit be 'd'. Then we want to find the integer solutions to ...

  n -1000d = n/9

  n -n/9 = 1000d . . . . . . add 1000d -n/9

  8n = 9000d . . . . . . . . multiply by 9

  n = 1125d . . . . . . . . . divide by 8

The values of d that will give a suitable 4-digit value of n are 1 through 7.

When d=8, n is 9000. Removing the 9 gives 0, not 1000.

When d=9, n is 10125, not a 4-digit number.

There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.

8 0
2 years ago
HELP PLSSSSS Triangle ABC is an equilateral triangle. The angle bisectors and the perpendicular bisectors meet at D in such a wa
vazorg [7]
CE = CD + DE = 2DE + DE = 3DE = 8.7

DE = 8.7/3 = 2.9
CD = 2DE = 5.8

For the inscribed circle, where center is point D. The radius is length DE.
This is because the circle will touch the 3 points where the bisectors intersect with sides of triangle.
radius = 2.9

For circumscribed circle, the center will also be point D. The radius is CD.
The circle will touch 3 points of triangle, A,B,C.
radius = 5.8
6 0
3 years ago
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